我有这样定义的员工和薪水表:
"name" (type: VARCHAR) "salary" (type: INTEGER)
我可以使用什么查询来获得该表中第二高的薪水?
这是关系的原因。
Name Salary Jim 6 Foo 5 Bar 5 Steve 4 SELECT name, salary FROM employees WHERE salary = (SELECT MAX(salary) FROM employees WHERE salary < (SELECT MAX(salary) FROM employees)) Result --> Bar 5, Foo 5
编辑: 我接受了Manoj的第二篇文章,对其进行了调整,并使它更具可读性。对我来说 n-1 不直观;但是,使用我想要的值是2 = 2nd,3 = 3rd等。
/* looking for 2nd highest salary -- notice the '=2' */ SELECT name,salary FROM employees WHERE salary = (SELECT DISTINCT(salary) FROM employees as e1 WHERE (SELECT COUNT(DISTINCT(salary))=2 FROM employees as e2 WHERE e1.salary <= e2.salary)) ORDER BY name Result --> Bar 5, Foo 5