使用BigQuery计算当日7天活跃用户？

admin

使用BigQuery计算当日7天活跃用户？

sql

如果我没有记错的话，计算当天活跃用户应该很简单。只需将今天和x天退回（7天有效将是6天退回），然后计算不同的ID。我有一个为期2天的活跃用户的以下查询：

WITH allTables AS (
  SELECT 
    CONCAT(user_dim.app_info.app_id, ':', user_dim.app_info.app_platform) AS app,
    event.date,
    user_dim.app_info.app_instance_id as users
  FROM `dataset.app_events_intraday_20170407`
  CROSS JOIN
    UNNEST(event_dim) AS event

  UNION ALL
  SELECT 
    CONCAT(user_dim.app_info.app_id, ':', user_dim.app_info.app_platform) AS app,
    event.date,
    user_dim.app_info.app_instance_id as users
  FROM `dataset.app_events_20170406`
  CROSS JOIN
    UNNEST(event_dim) AS event
) SELECT COUNT(DISTINCT(users)) AS unique,
   COUNT(users) as total
FROM allTables

这是为期2天的活动，但对于7天或30天，我只需要合并所有这些表即可。这是正确的还是需要修改？

阅读 171

2021-07-01

共1个答案

admin

而不是使用UNION ALL，您应该尝试使用 Querying Multiple Tables Using a Wildcard Table

尝试以下类似的方法

#standardSQL
WITH allTables AS (
  SELECT 
    CONCAT(user_dim.app_info.app_instance_id, ':', user_dim.app_info.app_platform) AS app,
    event.date,
    user_dim.app_info.app_instance_id AS users
  FROM `dataset.app_events_intraday_*`, UNNEST(event_dim) AS event
  WHERE _TABLE_SUFFIX BETWEEN '20170401' AND '20170407' 
  UNION ALL
  SELECT 
    CONCAT(user_dim.app_info.app_instance_id, ':', user_dim.app_info.app_platform) AS app,
    event.date,
    user_dim.app_info.app_instance_id AS users
  FROM `dataset.app_events_*`, UNNEST(event_dim) AS event
  WHERE _TABLE_SUFFIX BETWEEN '20170401' AND '20170407' 
) 
SELECT 
  COUNT(DISTINCT(users)) AS unique,
  COUNT(users) AS total
FROM allTables

您可以在下面的forWHERE子句中使用使其更通用

WHERE _TABLE_SUFFIX 
   BETWEEN FORMAT_DATE('%Y%m%d', DATE_SUB(CURRENT_DATE(), INTERVAL 6 DAY)) 
   AND FORMAT_DATE('%Y%m%d', CURRENT_DATE())

另请注意：我改变app_id在user_dim.app_info.app_id给app_instance_id，我认为这是在你的身边错字-
但我可能是错的

2021-07-01