我正在尝试从2个相似的结果(最旧的结果)中检索最后一个结果
FromUser | ToUser | Message | Date User1 | User2 | hi | 01/01/2013 20:00 User1 | User2 | hi later| 01/01/2013 21:00 User5 | User2 | hi | 01/01/2013 20:01 User5 | User2 | hi later| 01/01/2013 21:01 SELECT CM.FromUser, CM.ToUser, CM.Message, CM.Date, U.UserId, U.UserFullName, U.UserName, U.UserPhoto FROM ConversationMessages AS CM INNER JOIN Users AS U ON U.UserName = CM.FromUser WHERE CM.ToUser = @user ORDER BY CM.Date DESC
它应先列出用户5嗨,然后再列出用户1嗨,然后再列出(用户5在日期上较新)。只有最后一行基本上按FromUser日期分组,然后按日期排序。我对sql没用,在这里尝试了许多建议,但没有任何工作
FromUser
您想为此使用窗口函数,而不是group by:
group by
select FromUser, ToUser, Message, [Date], UserId, UserFullName, UserName, UserPhoto from (SELECT CM.FromUser, CM.ToUser, CM.Message, CM.Date, U.UserId, U.UserFullName, U.UserName, U.UserPhoto, row_number() over (partition by CM.FromUser, CM.ToUser order by [Date] desc) as seqnum FROM ConversationMessages CM INNER JOIN Users U ON U.UserName = CM.FromUser WHERE CM.ToUser = @user ) s WHERE seqnum = 1 ORDER BY CM.Date DESC ;