我正在使用这些Scanner方法nextInt()并nextLine()读取输入。

它看起来像这样：

System.out.println("Enter numerical value");    
int option;
option = input.nextInt(); // Read numerical value from input
System.out.println("Enter 1st string"); 
String string1 = input.nextLine(); // Read 1st string (this is skipped)
System.out.println("Enter 2nd string");
String string2 = input.nextLine(); // Read 2nd string (this appears right after reading numerical value)

问题是输入数值后，第一个input.nextLine()被跳过，第二个input.nextLine()被执行，这样我的输出是这样的：

Enter numerical value
3   // This is my input
Enter 1st string    // The program is supposed to stop here and wait for my input, but is skipped
Enter 2nd string    // ...and this line is executed and waits for my input

我测试了我的应用程序，看起来问题在于使用input.nextInt(). 如果我删除它，那么两者string1 = input.nextLine()都string2 = input.nextLine()将按照我的意愿执行。