我正在开发一个下拉菜单,该菜单使用HTML optgroups作为员工所属的组名。这是MySQL查询和输出:
mysql> SELECT employee.emp_id,employees.empname,employees.grp_id,groups.groupname FROM雇员离开的雇员加入员工组。grp_id= groups.grp_id,按组名asc排序; + -------- + ------------ + -------- + ----------- + | emp_id | empname | grp_id | 组名| + -------- + ------------ + -------- + ----------- + | 20 | 员工2 | 13 | 第1组| | 19 | 员工1 | 13 | 第1组| | 21 | 员工3 | 14 | 第2组| + -------- + ------------ + -------- + ----------- + 设置3行(0.00秒)
唯一的问题是,我很难确定如何使optgroup正常工作。我尝试了无数次,这真的开始让我感到沮丧。 以下是我想要的输出示例(示例):
<select name="dropdownmenu"> <optgroup label="Group 1"> <option name="20">Employee 2</option> <option name="19">Employee 1</option> </optgroup> <optgroup label="Group 2"> <option name="21">Employee 3</option> </optgroup> </select>
基本上,optgroup必须是“ groupname”,选项“ name”应该是“ emp_id”,而动作“ option”(下拉项)是“ empname”。
我希望这是可以做的,但是真的不确定。这是我所拥有的功能,但无法正常运行:
function getDynGrpList() { global $db; // $query = "SELECT * FROM employees ORDER BY grp_id desc;"; $query = "SELECT employees.emp_id,employees.empname,employees.grp_id,groups.groupname FROM employees left join groups on employees.grp_id = groups.grp_id order by groupname asc;"; $employees = $db->GetAll($query); $groups = array(); while ($qa = $employees->GetRows()) { $groups[$qa['groupname']][$qa['grp_id']] = $qa['empname']; } foreach ($groups as $label => $opt) { ?> <optgroup label="<?php echo $label; ?>"> <?php } foreach ($groups[$label] as $id => $name) { ?> <option value="<?php echo $id; ?>"><?php echo $name; ?></option> <?php } ?> </optgroup> <?php }
从凌晨3:15 CST(2/27)开始的getDynGrpList函数:
function getDynGrpList() { global $db; // $query = "SELECT * FROM employees ORDER BY grp_id desc;"; $query = "SELECT employees.emp_id,employees.empname,employees.grp_id,groups.groupname FROM employees left join groups on employees.grp_id = groups.grp_id order by groupname asc;"; $employees = $db->GetAll($query); $groups = array(); while ($qa = $employees->GetRows()) { $groups[$qa['groupname']][$qa['emp_id']] = $qa['empname']; } var_export($groups); foreach($groups as $label => $opt): ?> <optgroup label="<?php echo $label; ?>"> <?php foreach ($opt as $id => $name): ?> <option value="<?php echo $id; ?>"><?php echo $name; ?></option> <?php endforeach; ?> </optgroup> <?php endforeach; }
最终解决方案(在Felix Kling的帮助下)
function getDynGrpList() { global $db; $query = "SELECT employees.emp_id,employees.empname,employees.grp_id,groups.groupname FROM employees left join groups on employees.grp_id = groups.grp_id order by groupname asc;"; $employees = $db->GetAll($query); $groups = array(); foreach ($employees as $employee) { $groups[$employee['groupname']][$employee['emp_id']] = $employee['empname']; } foreach($groups as $label => $opt): ?> <optgroup label="<?php echo $label; ?>"> <?php foreach ($opt as $id => $name): ?> <option value="<?php echo $id; ?>"><?php echo $name; ?></option> <?php endforeach; ?> </optgroup> <?php endforeach; }
这两个for循环未嵌套在您的代码中:
foreach ($groups as $label => $opt) { ?> <optgroup label="<?php echo $label; ?>"> <?php } <-- wrong here foreach ($groups[$label] as $id => $name) { ?> <option value="<?php echo $id; ?>"><?php echo $name; ?></option> <?php } ?>
结果是首先创建了所有的opt组,然后添加了最后一个组的雇员(因为$label并且$opt在循环完成后也可以使用)。
$label
$opt
您必须嵌套循环( 对控制结构使用替代语法 ):
<?php foreach($groups as $label => $opt): ?> <optgroup label="<?php echo $label; ?>"> <?php foreach ($opt as $id => $name): ?> <option value="<?php echo $id; ?>"><?php echo $name; ?></option> <?php endforeach; ?> </optgroup> <?php endforeach; ?>
此外,我认为您在创建数组时必须使用emp_id,而不是grp_id:
emp_id
grp_id
while ($qa = $employees->GetRows()) { $groups[$qa['groupname']][$qa['emp_id']] = $qa['empname']; }