我正在编写一个非常简单的脚本来调用另一个脚本，我需要将参数从我当前的脚本传播到我正在执行的脚本。
例如，我的脚本名称是foo.sh并且调用bar.sh
foo.sh
bar.sh
foo.sh：
bar $1 $2 $3 $4
在不明确指定每个参数的情况下如何做到这一点？
如果您确实希望传递相同的参数，请使用"$@"而不是plain 。$@
"$@"
$@
观察：
$ cat no_quotes.sh #!/bin/bash echo_args.sh $@ $ cat quotes.sh #!/bin/bash echo_args.sh "$@" $ cat echo_args.sh #!/bin/bash echo Received: $1 echo Received: $2 echo Received: $3 echo Received: $4 $ ./no_quotes.sh first second Received: first Received: second Received: Received: $ ./no_quotes.sh "one quoted arg" Received: one Received: quoted Received: arg Received: $ ./quotes.sh first second Received: first Received: second Received: Received: $ ./quotes.sh "one quoted arg" Received: one quoted arg Received: Received: Received:
