我如何获得当前的一年中的周数,如 PHP 的date('W')?
date('W')
它应该是一年中的 ISO-8601 周数,从星期一开始的周数。
你应该可以在这里得到你想要的: _ http_ ://www.merlyn.demon.co.uk/js-date6.htm#YWD 。
同一站点上更好的链接是: _ Working with week_ 。
这是基于提供的链接和 Dommer 早期发布的一些代码。它已针对 _ http://www.merlyn.demon.co.uk/js- date6.htm#YWD_ 上的结果进行了轻微测试。请彻底测试,不提供任何保证。
在观察夏令时期间的日期和 1 月 1 日为星期五的年份存在问题。通过使用所有 UTC 方法修复。以下将相同的结果返回给 Moment.js。
/* For a given date, get the ISO week number * * Based on information at: * * THIS PAGE (DOMAIN EVEN) DOESN'T EXIST ANYMORE UNFORTUNATELY * http://www.merlyn.demon.co.uk/weekcalc.htm#WNR * * Algorithm is to find nearest thursday, it's year * is the year of the week number. Then get weeks * between that date and the first day of that year. * * Note that dates in one year can be weeks of previous * or next year, overlap is up to 3 days. * * e.g. 2014/12/29 is Monday in week 1 of 2015 * 2012/1/1 is Sunday in week 52 of 2011 */ function getWeekNumber(d) { // Copy date so don't modify original d = new Date(Date.UTC(d.getFullYear(), d.getMonth(), d.getDate())); // Set to nearest Thursday: current date + 4 - current day number // Make Sunday's day number 7 d.setUTCDate(d.getUTCDate() + 4 - (d.getUTCDay()||7)); // Get first day of year var yearStart = new Date(Date.UTC(d.getUTCFullYear(),0,1)); // Calculate full weeks to nearest Thursday var weekNo = Math.ceil(( ( (d - yearStart) / 86400000) + 1)/7); // Return array of year and week number return [d.getUTCFullYear(), weekNo]; } var result = getWeekNumber(new Date()); document.write('It\'s currently week ' + result[1] + ' of ' + result[0]);
创建“UTC”日期时,小时数归零。
最小化的原型版本(仅返回周数):
Date.prototype.getWeekNumber = function(){ var d = new Date(Date.UTC(this.getFullYear(), this.getMonth(), this.getDate())); var dayNum = d.getUTCDay() || 7; d.setUTCDate(d.getUTCDate() + 4 - dayNum); var yearStart = new Date(Date.UTC(d.getUTCFullYear(),0,1)); return Math.ceil((((d - yearStart) / 86400000) + 1)/7) }; document.write('The current ISO week number is ' + new Date().getWeekNumber());
在本节中,您可以输入 YYYY-MM-DD 格式的任何日期,并检查此代码给出的周数是否与 Moment.js ISO 周数相同(从 2000 年到 2050 年的 50 年测试)。
Date.prototype.getWeekNumber = function(){ var d = new Date(Date.UTC(this.getFullYear(), this.getMonth(), this.getDate())); var dayNum = d.getUTCDay() || 7; d.setUTCDate(d.getUTCDate() + 4 - dayNum); var yearStart = new Date(Date.UTC(d.getUTCFullYear(),0,1)); return Math.ceil((((d - yearStart) / 86400000) + 1)/7) }; function checkWeek() { var s = document.getElementById('dString').value; var m = moment(s, 'YYYY-MM-DD'); document.getElementById('momentWeek').value = m.format('W'); document.getElementById('answerWeek').value = m.toDate().getWeekNumber(); } <script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script> Enter date YYYY-MM-DD: <input id="dString" value="2021-02-22"> <button onclick="checkWeek(this)">Check week number</button><br> Moment: <input id="momentWeek" readonly><br> Answer: <input id="answerWeek" readonly>