小编典典

将数组划分为子序列数组

c#

我有一个字节数组:

byte[] bytes;  // many elements

我需要将其划分为X元素的字节数组的子序列。例如,x = 4。

如果bytes.Length通过X不乘,然后加上0至最后子阵列使 所有subsequnce的长度必须是X

Linq可用。

PS:我的尝试

static void Main(string[] args)
{
    List<byte> bytes = new List<byte>() { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 };

    int c = bytes.Count / 4;

    for (int i = 0; i <= c; i+=4)
    {
        int diff = bytes.Count - 4;

        if (diff < 0)
        {

        }
        else
        {
            List<byte> b = bytes.GetRange(i, 4);
        }
    }

    Console.ReadKey();
}

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2020-05-19

共1个答案

小编典典

这很可爱:

static class ChunkExtension
{
    public static IEnumerable<T[]> Chunkify<T>(
        this IEnumerable<T> source, int size)
    {
        if (source == null) throw new ArgumentNullException("source");
        if (size < 1) throw new ArgumentOutOfRangeException("size");
        using (var iter = source.GetEnumerator())
        {
            while (iter.MoveNext())
            {
                var chunk = new T[size];
                chunk[0] = iter.Current;
                for (int i = 1; i < size && iter.MoveNext(); i++)
                {
                    chunk[i] = iter.Current;
                }
                yield return chunk;
            }
        }
    }
}
static class Program
{
    static void Main(string[] args)
    {
        List<byte> bytes = new List<byte>() {
              1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 };
        var chunks = bytes.Chunkify(4);
        foreach (byte[] chunk in chunks)
        {
            foreach (byte b in chunk) Console.Write(b.ToString("x2") + " ");
            Console.WriteLine();
        }
    }
}
2020-05-19