我想通过json.net将此代码序列化:
public interface ITestInterface { string Guid {get;set;} } public class TestClassThatImplementsTestInterface1 { public string Guid { get;set; } } public class TestClassThatImplementsTestInterface2 { public string Guid { get;set; } } public class ClassToSerializeViaJson { public ClassToSerializeViaJson() { this.CollectionToSerialize = new List<ITestInterface>(); this.CollectionToSerialize.add( new TestClassThatImplementsTestInterface2() ); this.CollectionToSerialize.add( new TestClassThatImplementsTestInterface2() ); } List<ITestInterface> CollectionToSerialize { get;set; } }
我想使用json.net序列化/反序列化ClassToSerializeViaJson。序列化正在工作,但是反序列化给了我这个错误:
Newtonsoft.Json.JsonSerializationException:无法创建ITestInterface类型的实例。类型是接口或抽象类,无法实例化。
那么我如何反序列化List<ITestInterface>集合?
List<ITestInterface>
贝娄完整的工作示例,您想做什么:
public interface ITestInterface { string Guid { get; set; } } public class TestClassThatImplementsTestInterface1 : ITestInterface { public string Guid { get; set; } public string Something1 { get; set; } } public class TestClassThatImplementsTestInterface2 : ITestInterface { public string Guid { get; set; } public string Something2 { get; set; } } public class ClassToSerializeViaJson { public ClassToSerializeViaJson() { this.CollectionToSerialize = new List<ITestInterface>(); } public List<ITestInterface> CollectionToSerialize { get; set; } } public class TypeNameSerializationBinder : SerializationBinder { public string TypeFormat { get; private set; } public TypeNameSerializationBinder(string typeFormat) { TypeFormat = typeFormat; } public override void BindToName(Type serializedType, out string assemblyName, out string typeName) { assemblyName = null; typeName = serializedType.Name; } public override Type BindToType(string assemblyName, string typeName) { var resolvedTypeName = string.Format(TypeFormat, typeName); return Type.GetType(resolvedTypeName, true); } } class Program { static void Main() { var binder = new TypeNameSerializationBinder("ConsoleApplication.{0}, ConsoleApplication"); var toserialize = new ClassToSerializeViaJson(); toserialize.CollectionToSerialize.Add( new TestClassThatImplementsTestInterface1() { Guid = Guid.NewGuid().ToString(), Something1 = "Some1" }); toserialize.CollectionToSerialize.Add( new TestClassThatImplementsTestInterface2() { Guid = Guid.NewGuid().ToString(), Something2 = "Some2" }); string json = JsonConvert.SerializeObject(toserialize, Formatting.Indented, new JsonSerializerSettings { TypeNameHandling = TypeNameHandling.Auto, Binder = binder }); var obj = JsonConvert.DeserializeObject<ClassToSerializeViaJson>(json, new JsonSerializerSettings { TypeNameHandling = TypeNameHandling.Auto, Binder = binder }); Console.ReadLine(); } }