小编典典

序列化和反序列化.NET对象的最快方法

c#

我正在寻找序列化和反序列化.NET对象的最快方法。这是我到目前为止的内容:

public class TD
{
    public List<CT> CTs { get; set; }
    public List<TE> TEs { get; set; }
    public string Code { get; set; }
    public string Message { get; set; }
    public DateTime StartDate { get; set; }
    public DateTime EndDate { get; set; }

    public static string Serialize(List<TD> tData)
    {
        var serializer = new XmlSerializer(typeof(List<TD>));

        TextWriter writer = new StringWriter();
        serializer.Serialize(writer, tData);

        return writer.ToString();
    }

    public static List<TD> Deserialize(string tData)
    {
        var serializer = new XmlSerializer(typeof(List<TD>));

        TextReader reader = new StringReader(tData);

        return (List<TD>)serializer.Deserialize(reader);
    }        
}

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2020-05-19

共1个答案

小编典典

这是您使用protobuf-net的模型(已发明CTTE)(但仍保留了使用的能力,这可能很有用-特别是对于迁移);我谦虚地提出(如果需要的话,有很多证据)这
.NET中最快的(或者肯定是最快的)通用串行器之一。XmlSerializer __

如果需要字符串,只需将base-64编码即可。

[XmlType]
public class CT {
    [XmlElement(Order = 1)]
    public int Foo { get; set; }
}
[XmlType]
public class TE {
    [XmlElement(Order = 1)]
    public int Bar { get; set; }
}
[XmlType]
public class TD {
    [XmlElement(Order=1)]
    public List<CT> CTs { get; set; }
    [XmlElement(Order=2)]
    public List<TE> TEs { get; set; }
    [XmlElement(Order = 3)]
    public string Code { get; set; }
    [XmlElement(Order = 4)]
    public string Message { get; set; }
    [XmlElement(Order = 5)]
    public DateTime StartDate { get; set; }
    [XmlElement(Order = 6)]
    public DateTime EndDate { get; set; }

    public static byte[] Serialize(List<TD> tData) {
        using (var ms = new MemoryStream()) {
            ProtoBuf.Serializer.Serialize(ms, tData);
            return ms.ToArray();
        }            
    }

    public static List<TD> Deserialize(byte[] tData) {
        using (var ms = new MemoryStream(tData)) {
            return ProtoBuf.Serializer.Deserialize<List<TD>>(ms);
        }
    }
}
2020-05-19