小编典典

如何将Unix时间戳转换为DateTime,反之亦然?

c#

有此示例代码,但随后开始谈论毫秒/纳秒问题。

自M#的Unix时代以来 ,同样的问题在MSDN上,以
秒为单位

到目前为止,这是我得到的:

public Double CreatedEpoch
{
  get
  {
    DateTime epoch = new DateTime(1970, 1, 1, 0, 0, 0, 0).ToLocalTime();
    TimeSpan span = (this.Created.ToLocalTime() - epoch);
    return span.TotalSeconds;
  }
  set
  {
    DateTime epoch = new DateTime(1970, 1, 1, 0, 0, 0, 0).ToLocalTime();
    this.Created = epoch.AddSeconds(value);
  }
}

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2020-05-19

共1个答案

小编典典

这是您需要的:

public static DateTime UnixTimeStampToDateTime( double unixTimeStamp )
{
    // Unix timestamp is seconds past epoch
    System.DateTime dtDateTime = new DateTime(1970,1,1,0,0,0,0,System.DateTimeKind.Utc);
    dtDateTime = dtDateTime.AddSeconds( unixTimeStamp ).ToLocalTime();
    return dtDateTime;
}

或者,对于Java(这是不同的,因为时间戳以毫秒为单位,而不是秒):

public static DateTime JavaTimeStampToDateTime( double javaTimeStamp )
{
    // Java timestamp is milliseconds past epoch
    System.DateTime dtDateTime = new DateTime(1970,1,1,0,0,0,0,System.DateTimeKind.Utc);
    dtDateTime = dtDateTime.AddMilliseconds( javaTimeStamp ).ToLocalTime();
    return dtDateTime;
}
2020-05-19