我正在用C#创建一个应用程序。它的功能是评估给定是否为质数,以及相同的交换数是否为质数。
当我在Visual Studio中构建解决方案时,它说“非静态字段,方法或属性需要对象引用”。我在使用“ volteado”和“ siprimo”方法时遇到了这个问题。
问题出在哪里,我该如何解决?
namespace ConsoleApplication1 { class Program { static void Main(string[] args) { Console.Write("Write a number: "); long a= Convert.ToInt64(Console.ReadLine()); // a is the number given by the user long av = volteado(a); // av is "a" but swapped if (siprimo(a) == false && siprimo(av) == false) Console.WriteLine("Both original and swapped numbers are prime."); else Console.WriteLine("One of the numbers isnt prime."); Console.ReadLine(); } private bool siprimo(long a) { // Evaluate if the received number is prime bool sp = true; for (long k = 2; k <= a / 2; k++) if (a % k == 0) sp = false; return sp; } private long volteado(long a) { // Swap the received number long v = 0; while (a > 0) { v = 10 * v + a % 10; a /= 10; } return v; } } }
您不能从静态方法访问非静态成员。(请注意,这Main()是静态的,这是.Net的要求)。通过将static关键字放在siprimo和volteado之前,使它们固定为静态。例如:
Main()
static private long volteado(long a)