问题是,我需要知道,如果它的3.5版本SP 1 Environment.Version()只的回报2.0.50727.3053。
Environment.Version()
2.0.50727.3053
我找到了这个解决方案,但是我认为这将花费更多的时间,所以我正在寻找一个更简单的解决方案。可能吗?
这样的事情应该做。只需从注册表中获取价值
对于.NET 1-4 :
Framework是已安装的最高版本,SP是该版本的Service Pack。
Framework
SP
RegistryKey installed_versions = Registry.LocalMachine.OpenSubKey(@"SOFTWARE\Microsoft\NET Framework Setup\NDP"); string[] version_names = installed_versions.GetSubKeyNames(); //version names start with 'v', eg, 'v3.5' which needs to be trimmed off before conversion double Framework = Convert.ToDouble(version_names[version_names.Length - 1].Remove(0, 1), CultureInfo.InvariantCulture); int SP = Convert.ToInt32(installed_versions.OpenSubKey(version_names[version_names.Length - 1]).GetValue("SP", 0));
对于.NET 4.5+ (根据官方文档):
using System; using Microsoft.Win32; ... private static void Get45or451FromRegistry() { using (RegistryKey ndpKey = RegistryKey.OpenBaseKey(RegistryHive.LocalMachine, RegistryView.Registry32).OpenSubKey("SOFTWARE\\Microsoft\\NET Framework Setup\\NDP\\v4\\Full\\")) { int releaseKey = Convert.ToInt32(ndpKey.GetValue("Release")); if (true) { Console.WriteLine("Version: " + CheckFor45DotVersion(releaseKey)); } } } ... // Checking the version using >= will enable forward compatibility, // however you should always compile your code on newer versions of // the framework to ensure your app works the same. private static string CheckFor45DotVersion(int releaseKey) { if (releaseKey >= 461808) { return "4.7.2 or later"; } if (releaseKey >= 461308) { return "4.7.1 or later"; } if (releaseKey >= 460798) { return "4.7 or later"; } if (releaseKey >= 394802) { return "4.6.2 or later"; } if (releaseKey >= 394254) { return "4.6.1 or later"; } if (releaseKey >= 393295) { return "4.6 or later"; } if (releaseKey >= 393273) { return "4.6 RC or later"; } if ((releaseKey >= 379893)) { return "4.5.2 or later"; } if ((releaseKey >= 378675)) { return "4.5.1 or later"; } if ((releaseKey >= 378389)) { return "4.5 or later"; } // This line should never execute. A non-null release key should mean // that 4.5 or later is installed. return "No 4.5 or later version detected"; }