这是我的尝试,这只是我的代码的一部分:
final double RADIUS = 6371.01; double temp = Math.cos(Math.toRadians(latA)) * Math.cos(Math.toRadians(latB)) * Math.cos(Math.toRadians((latB) - (latA))) + Math.sin(Math.toRadians(latA)) * Math.sin(Math.toRadians(latB)); return temp * RADIUS * Math.PI / 180;
我正在使用以下公式来获取经度和纬度:
x = Deg + (Min + Sec / 60) / 60)
上面Dommer给出的Java代码给出的结果略有不正确,但是如果你正在处理GPS轨迹,则小错误加起来。这是Java中Haversine方法的实现,该方法还考虑了两点之间的高度差。
/** * Calculate distance between two points in latitude and longitude taking * into account height difference. If you are not interested in height * difference pass 0.0. Uses Haversine method as its base. * * lat1, lon1 Start point lat2, lon2 End point el1 Start altitude in meters * el2 End altitude in meters * @returns Distance in Meters */ public static double distance(double lat1, double lat2, double lon1, double lon2, double el1, double el2) { final int R = 6371; // Radius of the earth double latDistance = Math.toRadians(lat2 - lat1); double lonDistance = Math.toRadians(lon2 - lon1); double a = Math.sin(latDistance / 2) * Math.sin(latDistance / 2) + Math.cos(Math.toRadians(lat1)) * Math.cos(Math.toRadians(lat2)) * Math.sin(lonDistance / 2) * Math.sin(lonDistance / 2); double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a)); double distance = R * c * 1000; // convert to meters double height = el1 - el2; distance = Math.pow(distance, 2) + Math.pow(height, 2); return Math.sqrt(distance); }