我将尝试忽略其他细节并将其简短化：

@Entity
public class User
    @UniqueEmail
    @Column(unique = true)
    private String email;
}

@Component
public class UniqueEmailValidatior implements ConstraintValidator<UniqueEmail,String>, InitializingBean {

    @Autowired private UserService userService;

    @Override
    public void initialize(UniqueEmail constraintAnnotation) {

    }

    @Override
    public boolean isValid(String value, ConstraintValidatorContext context) {
        if(userService == null) throw new IllegalStateException();
        if(value == null) return false;
        return !userService.isEmailExisted(value);
    }

}

当在Spring中进行验证（Spring MVC @Valid或注入Validatorusing
@Autowire）时，这将起作用，一切都会好起来的。但是，一旦我使用Spring Data JPA保存了实体：

User save = userRepository.save(newUser);

Hibernate将尝试在UniqueEmailValidatior不注入UserServicebean的情况下实例化一个新对象。因此，如何使Hibernate在UniqueEmailValidatior不实例化新组件的情况下使用我的组件。我可以使用禁用hibernate验证，spring.jpa.properties.javax.persistence.validation.mode=none但我希望有另一种方法

更新：这是我的UserService：

   @Autowired private Validator validator;
   @Transactional
    public SimpleUserDTO newUser(UserRegisterDTO user) {
        validator.validate(user);
        System.out.println("This passes");
        User newUser = new User(user.getUsername(),
                passwordEncoder.encode(user.getPassword()),user.getEmail(),
                "USER",
                user.getAvatar());
        User save = userRepository.save(newUser);
        System.out.println("This won't pass");
        return ....
    }