Spring Boot-多个模板位置

小编典典

Spring Boot-多个模板位置

spring-boot

我希望Spring在不同的位置查找模板，而不仅仅是在src/main/resource/templates/。

我这里有

@Configuration
public class WebConfig{

    @Autowired
    private SpringTemplateEngine templateEngine;

    @PostConstruct
    public void clientTemplate(){
        SpringResourceTemplateResolver resolver = new SpringResourceTemplateResolver();
        resolver.setPrefix("static/client");
        resolver.setSuffix(".html");
        resolver.setTemplateMode("HTML5");
        resolver.setOrder(templateEngine.getTemplateResolvers().size());
        resolver.setCacheable(false);
        templateEngine.addTemplateResolver(resolver);
    }
}

但是，当我尝试访问中的现有模板 index.html 时/src/main/resources/static/client，我得到了：

java.lang.IllegalArgumentException: ApplicationContext has not been initialized in resource resolver. TemplateResolver or ResourceResolver might not have been correctly configured by the Spring Application Context.
at org.thymeleaf.util.Validate.notNull(Validate.java:37)
at org.thymeleaf.spring4.resourceresolver.SpringResourceResourceResolver.getResourceAsStream(SpringResourceResourceResolver.java:81)
at org.thymeleaf.TemplateRepository.getTemplate(TemplateRepository.java:221)
at org.thymeleaf.TemplateEngine.process(TemplateEngine.java:1104)
at org.thymeleaf.TemplateEngine.process(TemplateEngine.java:1060)
at org.thymeleaf.TemplateEngine.process(TemplateEngine.java:1011)
at org.thymeleaf.spring4.view.ThymeleafView.renderFragment(ThymeleafView.java:335)
at org.thymeleaf.spring4.view.ThymeleafView.render(ThymeleafView.java:190)
at org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1257)
at org.springframework.web.servlet.DispatcherServlet.processDispatchResult(DispatcherServlet.java:1037)
at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:980)
at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:897)
at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:970)
at org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:861)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:622)
at org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:846)

如何解决这个问题？

阅读 548

2020-05-30

共1个答案

小编典典

1.非Spring管理的SpringResourceTemplateResolver

使用当前设置，您将在方法中创建的实例SpringResourceTemplateResolver，而
不是@Bean。因此，它不会在spring被捡起，您需要提供ApplicationContext（示例）：

SpringResourceTemplateResolver resolver = new SpringResourceTemplateResolver();
resolver.setApplicationContext(applicationContext);
resolver.setPrefix("/WEB-INF/templates/");
resolver.setTemplateMode(TemplateMode.HTML);

注意 resolver.setApplicationContext(applicationContext);

2. Spring托管的SpringResourceTemplateResolver

您可能会看到不需要这样做的示例，但是它们肯定是SpringResourceTemplateResolver在@Bean方法中创建实例的。Spring将其拾取并为您设置应用程序上下文（示例）：

@Bean
public ITemplateResolver templateResolver() {
    SpringResourceTemplateResolver resolver = new SpringResourceTemplateResolver();
    resolver.setPrefix("/WEB-INF/templates/");
    resolver.setSuffix(".html");
    resolver.setTemplateMode(TemplateMode.HTML);
    resolver.setCacheable(false);
    return resolver;
}

2020-05-30