小编典典

HTTP状态406。Spring MVC 4.0,jQuery,JSON

spring-mvc

我想从控制器发送JSON。我有以下配置。

spring-servlet.xml:

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:mvc="http://www.springframework.org/schema/mvc"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
           http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
           http://www.springframework.org/schema/mvc
           http://www.springframework.org/schema/mvc/spring-mvc.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">

    <mvc:annotation-driven/>

    <mvc:resources mapping="/resources/**" location="/resources/"/>
    <context:component-scan base-package="com.castle.controllers"/>

    <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
        <property name="prefix" value="/views/"/>
        <property name="suffix" value=".jsp"/>
    </bean>
</beans>

.js:

function testAjax() {
    var data = {userName: "MyUsername", password:"Password"};
    $.ajax({
        url: 'ajax/test.htm',
        dataType : 'json',
        type : 'POST',
        contentType: "application/json",
        data: JSON.stringify(data),
        success: function(response){
            alert('Load was performed.');
        }
    });
}

UserTest.java:

public class UserTest {
    private String userName;
    private String password;

    public String getUserName() {
        return userName;
    }

    public void setUserName(String userName) {
        this.userName = userName;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }
}

TestAjaxController.java:

@Controller
@RequestMapping("/ajax")
public class TestAjaxController {

    @RequestMapping(method = RequestMethod.POST, value = "/test.htm")
    public @ResponseBody
    UserTest testAjaxRequest(@RequestBody UserTest user) {
        return user;
    }
}

pom.xml:

    <dependency>
                <groupId>org.codehaus.jackson</groupId>
                <artifactId>jackson-mapper-asl</artifactId>
                <version>1.9.13</version>
            </dependency>
            <dependency>
                <groupId>org.codehaus.jackson</groupId>
                <artifactId>jackson-core-asl</artifactId>
                <version>1.9.13</version>
</dependency>

当我执行此请求时,我进入了表示为UserTest对象的Controller JSON。但返回时:

HTTP状态406-此请求标识的资源仅能够生成具有根据请求“接受”标头不可接受的特征的响应。

我做错了什么?我知道,关于此类情况有很多问题,但我无法在两天内解决…

更新 我已经找到了解决方案!只需要返回一个对象。不是用户对象或其他东西。但 return Object;

 public @ResponseBody Object testAjaxRequest(@RequestBody UserTest user) {
        List<UserTest> list = new ArrayList<>();
        list.add(user);
        list.add(user);
        list.add(user);
        return list;

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2020-06-01

共1个答案

小编典典

这里的主要问题是,"/test.htm"在检查Accept标头的值之前,路径将首先使用内容协商。使用扩展名*.htm,Spring将使用org.springframework.web.accept.ServletPathExtensionContentNegotiationStrategy和来确定要返回的可接受的媒体类型text/htmlMappingJacksonHttpMessageConverter产生的媒体类型不匹配,即。application/json因此返回406。

一种简单的解决方案是将路径更改为,类似于/test,其中基于该路径的内容协商不会解析响应的任何内容类型。相反,ContentNegotiationStrategy基于标头的其他内容将解析标头的值Accept

复杂的解决方案是更改处理的ContentNegotiationStrategy对象在上注册的对象的顺序。RequestResponseBodyMethodProcessor``@ResponseBody

2020-06-01