我试图弄清楚如何在每周的星期日运行crontab作业。我认为以下方法应该有效,但是我不确定我是否正确理解。以下正确吗?
5 8 * * 6
这是crontab格式的说明。
# 1. Entry: Minute when the process will be started [0-60] # 2. Entry: Hour when the process will be started [0-23] # 3. Entry: Day of the month when the process will be started [1-28/29/30/31] # 4. Entry: Month of the year when the process will be started [1-12] # 5. Entry: Weekday when the process will be started [0-6] [0 is Sunday] # # all x min = */x
因此,据此,您5 8 * * 0将在每个星期日8:05运行。
5 8 * * 0