我需要使用C语言显示本地计算机上的所有IP地址。如何才能做到这一点?
#include <stdio.h> #include <stropts.h> #include <sys/socket.h> #include <sys/ioctl.h> #include <linux/netdevice.h> #include <arpa/inet.h> #include <netinet/in.h> #include <unistd.h> int print_addresses(const int domain) { int s; struct ifconf ifconf; struct ifreq ifr[50]; int ifs; int i; s = socket(domain, SOCK_STREAM, 0); if (s < 0) { perror("socket"); return 0; } ifconf.ifc_buf = (char *) ifr; ifconf.ifc_len = sizeof ifr; if (ioctl(s, SIOCGIFCONF, &ifconf) == -1) { perror("ioctl"); return 0; } ifs = ifconf.ifc_len / sizeof(ifr[0]); printf("interfaces = %d:\n", ifs); for (i = 0; i < ifs; i++) { char ip[INET_ADDRSTRLEN]; struct sockaddr_in *s_in = (struct sockaddr_in *) &ifr[i].ifr_addr; if (!inet_ntop(domain, &s_in->sin_addr, ip, sizeof(ip))) { perror("inet_ntop"); return 0; } printf("%s - %s\n", ifr[i].ifr_name, ip); } close(s); return 1; } int main(int argc, char *argv[]) { int domains[] = { AF_INET, AF_INET6 }; int i; for (i = 0; i < sizeof(domains) / sizeof(domains[0]); i++) if (!print_addresses(domains[i])) return 1; return 0; }