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创建包含已分配数组的unique_ptr的正确方法

linux

创建一个unique_ptr来保存在免费存储中分配的数组的正确方法是什么?Visual Studio
2013默认情况下支持此功能,但是当我在Ubuntu上使用gcc版本4.8.1时,会出现内存泄漏和未定义的行为。

可以使用以下代码重现该问题:

#include <memory>
#include <string.h>

using namespace std;

int main()
{
    unique_ptr<unsigned char> testData(new unsigned char[16000]());

    memset(testData.get(),0x12,0);

    return 0;
}

Valgrind将给出以下输出:

==3894== 1 errors in context 1 of 1:
==3894== Mismatched free() / delete / delete []
==3894==    at 0x4C2BADC: operator delete(void*) (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==3894==    by 0x400AEF: std::default_delete<unsigned char>::operator()(unsigned char*) const (unique_ptr.h:67)
==3894==    by 0x4009D0: std::unique_ptr<unsigned char, std::default_delete<unsigned char> >::~unique_ptr() (unique_ptr.h:184)
==3894==    by 0x4007A9: main (test.cpp:19)
==3894==  Address 0x5a1a040 is 0 bytes inside a block of size 16,000 alloc'd
==3894==    at 0x4C2AFE7: operator new[](unsigned long) (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==3894==    by 0x40075F: main (test.cpp:15)

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2020-06-07

共1个答案

小编典典

使用T[]专业化:

std::unique_ptr<unsigned char[]> testData(new unsigned char[16000]());

请注意,在理想情况下,不必显式使用new实例化unique_ptr,从而避免了潜在的异常安全隐患。为此,C ++
14为您提供了std::make_unique功能模板。有关更多详细信息,请参见此出色的GOTW。语法为:

auto testData = std::make_unique<unsigned char[]>(16000);
2020-06-07