我是multiprocessing模块的新手。我只是尝试创建以下内容：我有一个工作是从RabbitMQ获取消息并将其传递到内部队列（multiprocessing.Queue）。然后，我想做的是：在收到新消息时生成一个进程。它可以工作，但是在完成工作后，它留下了一个僵尸进程，不会被其父进程终止。这是我的代码：

主要过程：

 #!/usr/bin/env python

 import multiprocessing
 import logging
 import consumer
 import producer
 import worker
 import time
 import base

 conf = base.get_settings()
 logger = base.logger(identity='launcher')

 request_order_q = multiprocessing.Queue()
 result_order_q = multiprocessing.Queue()

 request_status_q = multiprocessing.Queue()
 result_status_q = multiprocessing.Queue()

 CONSUMER_KEYS = [{'queue':'product.order',
                   'routing_key':'product.order',
                   'internal_q':request_order_q}]
 #                 {'queue':'product.status',
 #                  'routing_key':'product.status',
 #                  'internal_q':request_status_q}]

 def main():
     # Launch consumers
     for key in CONSUMER_KEYS:
         cons = consumer.RabbitConsumer(rabbit_q=key['queue'],
                                        routing_key=key['routing_key'],
                                        internal_q=key['internal_q'])
         cons.start()

     # Check reques_order_q if not empty spaw a process and process message
     while True:
         time.sleep(0.5)
         if not request_order_q.empty():
             handler = worker.Worker(request_order_q.get())
             logger.info('Launching Worker')
             handler.start()

 if __name__ == "__main__":
     main()

这是我的工人：

 import multiprocessing
 import sys 
 import time
 import base

 conf = base.get_settings()
 logger = base.logger(identity='worker')

 class Worker(multiprocessing.Process):

     def __init__(self, msg):
         super(Worker, self).__init__()
         self.msg = msg 
         self.daemon = True

     def run(self):
         logger.info('%s' % self.msg)
         time.sleep(10)
         sys.exit(1)

因此，在处理完所有消息之后，我可以看到带有ps aux命令的进程。但是我真的希望它们一旦完成就可以终止。谢谢。