jsp getServletContext（）错误

小编典典

jsp getServletContext（）错误

jsp

html

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Murach's Java Servlets and JSP</title>
</head>

<body>
    <%-- import packages and classes needed by the scripts --%>
    <%@ page import="business.*, data.*" %>

    <%
        //get parameters from the request
        String firstName = request.getParameter("firstName");
        String lastName = request.getParameter("lastName");
        String emailAddress = request.getParameter("emailAddress");

        // get the real path for the EmailList.txt file
        ServletContext sc = this.getServletContext();
        String path = sc.getRealPath("/WEB-INF/EmailList.txt");

        // use regular Java objects
        User user = new User(firstName, lastName, emailAddress);
        UserIO.add(user, path);
    %>
    <h1>Thanks for joining our email list</h1>
    <p>Here is the information that you entered: </p>
    <table cellspacing="5" cellpadding="5" border="1">
        <tr>
            <td align="right">First name:</td>
            <td><%= firstName %></td>
        </tr>
        <tr>
            <td align="right">Last name:</td>
            <td><%= lastName %></td>
        </tr>
        <tr>
            <td align="right">Email Address:</td>
            <td><%= emailAddress %></td>
        </tr>
    </table>

    <p>To enter another email address, click on the Back <br />
    button in your browser or the Return button shown <br />
    below.</p>

    <form action="index.jsp" method="post">
        <input type="submit" value="Return" />
    </form>

</body>
</html>

这给了我这个错误页面…

``C：\ bea \ user_projects \ domains \ mydomain。\ myserver.wlnotdelete \
extract \ myserver_sample01_WebContent \
jsp_servlet__display_email_entry.java’‘的编译
失败： C：\ bea \ user_projects \ domains \ mydomain。\ myserver.wlnotdelete \
extract \ my \ server_sample_ent .java：140：
由于/display_email_entry.jsp第19行中的错误，可能无法解析符号：
ServletContext sc = this.getServletContext （）;

完整的编译器错误： C：\ bea \ user_projects \ domains \ mydomain。\
myserver.wlnotdelete \ extract \ myserver_sample01_WebContent \
jsp_servlet__display_email_entry.java：140：无法解析符号
symbol：方法getServletContext（）
位置：类jsp_servlet .__ display_email_entry
ServletContext sc = this.getServletContext（）; // [/
display_email_entry.jsp; Line：19] ^

1 error
Thu Jun 03 15:56:09 CST 2010

有什么提示吗？我真的是JSP的新手，这是我的第一次学习实践… google.com找不到它。

谢谢！

阅读 251

2020-06-08

共1个答案

小编典典

Weblogic中的JSP在getServletContext方面的行为与Tomcat不同

更换 ServletContext sc = this.getServletContext();

至 ServletContext sc = getServletConfig().getServletContext();

2020-06-08