小编典典

Servlet“已启动线程但未能停止它” – Tomcat中的内存泄漏

tomcat

Apache Tomcat多次说过:

Web应用程序[/ MyServlet]似乎已启动名为[pool-61-thread-2]的线程,但未能停止它。这很可能造成内存泄漏。

这很危险吗?该Servlet应该每天能够处理10.000个请求。完成后如何关闭线程?

class Worker {

        private final CountDownLatch startSignal;
        private final CountDownLatch doneSignal;
        private final int threadNumber;

        Worker(
                CountDownLatch startSignal,
                CountDownLatch doneSignal,
                int threadNumber
        ){

            this.startSignal = startSignal;
            this.doneSignal = doneSignal;
            this.threadNumber = threadNumber;

        }

        public String[][] getSomeStrArrArr() {

            String[][] isRs = new String[8][20];
            String[][] inRs = new String[8][20];
            String[][] iwRs = new String[8][20];

            try {

                startSignal.await();

                if (threadNumber == 1) {
                    // get String[][] result for thread number 1
                    isRs = getIS(erg1, erg2, request);

                }

                if (threadNumber == 2) {
                    // get String[][] result for thread number 2
                    inRs = getIN(search_plz, request);
                }

                if (threadNumber == 3) {
                    // get String[][] result for thread number 3
                    iwRs = getIW(erg1, erg2, request);
                }

                doneSignal.countDown();

            } catch (InterruptedException ex) {

                System.out.println(
                        "Thread number "+threadNumber+" has been interrupted."
                );

            }
            if (threadNumber == 1) {
                return isRs;
            }
            if (threadNumber == 2) {
                return inRs;
            }
            if (threadNumber == 3) {
                return iwRs;
            }
            return null;
        }


        public Callable<String[][]> getSomeCallableStrArrArr(){
            return new Callable<String[][]>() {
                public String[][] call() throws Exception {
                    return getSomeStrArrArr();
                }
            };
        }

    }

    ExecutorService pool = Executors.newFixedThreadPool(3);
    Set<Future<String[][]>> set = new HashSet<Future<String[][]>>();
    CountDownLatch startSignal = new CountDownLatch(1);
    CountDownLatch doneSignal = new CountDownLatch(3);
    for (int i=1;i<=3;i++) {
        Worker worker = new Worker(startSignal,doneSignal,i);
        Callable<String[][]> callable =
                worker.getSomeCallableStrArrArr();
        Future<String[][]> future = pool.submit(callable);
        set.add(future);
    }
    startSignal.countDown();
    try {
        doneSignal.await();

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2020-06-16

共1个答案

小编典典

是的,这是一个问题。如果您的代码启动非守护程序线程,则这些线程将继续工作,直到退出运行方法。即使其他一切都完成了,当这些线程继续运行时,旧的JVM仍会徘徊。如果启动新实例,则可能会出现旧线程仍在与新实例创建的线程一起工作的情况。

必须对任务进行设计,以使它们对中断做出响应(这与吃异常并继续进行操作相反,这是您的示例所显示的)。这意味着检查当前线程上的中断标志,并以一种有用的方式捕获InterruptedException,该异常允许任务中断其工作并在需要时重置中断标志。ExecutorService实现具有shutdownNow方法,该方法将中断当前任务。

2020-06-16