小编典典

NoInitialContextException错误Tomcat

tomcat

我一直在尝试在这里找到解决方案,但是我不能…我有以下代码,但出现此错误。

我想念什么吗?谢谢 :)

package src;
import java.sql.DriverManager;
import java.sql.Connection;
import java.sql.SQLException;
import java.sql.Statement;
import java.sql.Wrapper;
import java.util.Hashtable;
import java.util.Properties;
import java.io.*;
import javax.*;
import javax.activation.DataSource;
import javax.naming.Context;
import javax.naming.InitialContext;
import javax.naming.NamingException;
import oracle.jdbc.pool.OracleDataSource;

public class TestServlet {

    @SuppressWarnings("unused")
    public static void main(String[] argv) throws SQLException, NamingException {

        Context initialContext = new InitialContext();
        if ( initialContext == null){System.out.println("initialContext null");}
        else {System.out.println("initialContext");}

        // Get DataSource
        Context environmentContext = (Context)initialContext.lookup("java:/comp/env");
        if ( environmentContext == null){System.out.println("envContext null.");}
        else {System.out.println("envContext");}

        DataSource ds = (DataSource)environmentContext.lookup("jdbc/testdb");



        System.out.println("\n -------- Oracle JDBC Connection Testing ------");

        try {

            Connection jdbcConnection = ((Statement) ds).getConnection();
            OracleDataSource ods = ((Wrapper) ds).unwrap(OracleDataSource.class);
            jdbcConnection.close();

        } catch (SQLException e) {

            System.out.println("Connection Failed! Check output console");
            e.printStackTrace();
            return;

        }

        String message = "You are connected!";
        System.out.println(message);

    }

}

context.xml

<Context>
    <Resource name="jdbc/testdb"
    auth="Container"
    type="javax.sql.DataSource" 
    maxActive="100"
    maxIdle="30"
    maxWait="10000" 
    username="dba01"
    password="qvE-g7Cacontext.xml"
    driverClassName="com.mysql.jdbc.Driver" 
    url="jdbc:oracle:thin:@10.0.1.6:1521:xe"/>
</Context>

错误

Exception in thread "main" javax.naming.NoInitialContextException: Need to specify class name in environment or system property, or as an applet parameter, or in an application resource file:  java.naming.factory.initial
    at javax.naming.spi.NamingManager.getInitialContext(Unknown Source)
    at javax.naming.InitialContext.getDefaultInitCtx(Unknown Source)
    at javax.naming.InitialContext.getURLOrDefaultInitCtx(Unknown Source)
    at javax.naming.InitialContext.lookup(Unknown Source)
    at src.TestServlet.main(TestServlet.java:34)

如果您需要更多信息,请告诉我!


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2020-06-16

共1个答案

小编典典

您需要一个初始上下文工厂。对于Tomcat,它是org.apache.naming.java.javaURLContextFactory

        System.setProperty(Context.INITIAL_CONTEXT_FACTORY,
                  "org.apache.naming.java.javaURLContextFactory");
2020-06-16