在我的Web应用程序中，我偶尔会使用可重复使用的邮件发送器应用程序发送电子邮件，如下所示：
user - self.user subject = ("My subject") from = "me@mydomain.com" message = render_to_string("welcomeEmail/welcome.eml", { "user" : user, }) send_mail(subject, message, from, [email], priority="high" )
我想发送一封带有嵌入式图像的电子邮件，因此我尝试在邮件客户端中制作邮件，查看源并将其放入模板（welcome.eml）中，但是我一直无法获取它来呈现发送时在邮件客户端中正确显示。
有谁知道我有一种简单的方法来创建带有内嵌图像的mime编码的邮件模板，这些模板在我发送邮件时会正确呈现？
这个问题的情况略有不同。我们并不是要寻求本身的替代，而是要将相关的部分附加到替代之一。在HTML版本中（是否拥有纯文本版本都没有关系），我们希望嵌入图像数据部分。不是内容的替代视图，而是HTML正文中引用的相关内容。
仍然可以发送嵌入的图像，但是我看不到使用的直接方法send_mail。现在该放弃便捷功能并EmailMessage直接实例化一个实例了。
send_mail
EmailMessage
这是对先前示例的更新：
from django.core.mail import EmailMessage from email.mime.image import MIMEImage from email.mime.multipart import MIMEMultipart from email.mime.text import MIMEText # Load the image you want to send as bytes img_data = open('logo.jpg', 'rb').read() # Create a "related" message container that will hold the HTML # message and the image. These are "related" (not "alternative") # because they are different, unique parts of the HTML message, # not alternative (html vs. plain text) views of the same content. html_part = MIMEMultipart(_subtype='related') # Create the body with HTML. Note that the image, since it is inline, is # referenced with the URL cid:myimage... you should take care to make # "myimage" unique body = MIMEText('<p>Hello <img src="cid:myimage" /></p>', _subtype='html') html_part.attach(body) # Now create the MIME container for the image img = MIMEImage(img_data, 'jpeg') img.add_header('Content-Id', '<myimage>') # angle brackets are important img.add_header("Content-Disposition", "inline", filename="myimage") # David Hess recommended this edit html_part.attach(img) # Configure and send an EmailMessage # Note we are passing None for the body (the 2nd parameter). You could pass plain text # to create an alternative part for this message msg = EmailMessage('Subject Line', None, 'foo@bar.com', ['bar@foo.com']) msg.attach(html_part) # Attach the raw MIMEBase descendant. This is a public method on EmailMessage msg.send()
