我试图使声明式交易工作。
这是我的spring.xml文件:
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation= "http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="url" value="jdbc:h2:tcp://my/db/path" /> <property name="username" value="username" /> <property name="password" value="password" /> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="packagesToScan" value="data" /> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.H2Dialect</prop> <prop key="hibernate.current_session_context_class">thread</prop> <prop key="hibernate.transaction.factory_class">org.hibernate.transaction.JDBCTransactionFactory</prop> <prop key="hibernate.show_sql">true</prop> <prop key="hibernate.hbm2ddl.auto">update</prop> </props> </property> </bean> <context:component-scan base-package="test" /> <tx:annotation-driven/> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory" /> </bean> </beans>
这是我的控制器实现:
//file TestController.java public interface TestController { public List<Test> findAll(); } //file TestControllerImp.java @Controller public class TestControllerImp implements TestController{ @Autowired private SessionFactory sessionFactory; /** * @return the sessionFactory */ public SessionFactory getSessionFactory() { return sessionFactory; } /** * @param sessionFactory the sessionFactory to set */ public void setSessionFactory(SessionFactory sessionFactory) { this.sessionFactory=sessionFactory; } @Transactional public List<Test> findAll() { return sessionFactory.getCurrentSession().createQuery("from Test").list(); } }
两者都在称为test的包中。
这是我的尝试:
TestController tc=context.getBean(TestController.class); List<Test> list=tc.findAll();
但这引发了异常:
org.hibernate.HibernateException:如果没有活动事务,createQuery无效
为什么transactionManager不起作用?我希望使用@Transactional批注将所有事务由Spring框架管理。我能做什么?
谢谢大家
删除以下行,当Spring管理事务时,不需要它们:
<prop key="hibernate.current_session_context_class">thread</prop> <prop key="hibernate.transaction.factory_class">org.hibernate.transaction.JDBCTransactionFactory</prop>
实际上,设置hibernate.current_session_context_class有效地禁用了Spring事务管理,请参阅AbstractSessionFactoryBean.setExposeTransactionAwareSessionFactory()javadoc:
hibernate.current_session_context_class
AbstractSessionFactoryBean.setExposeTransactionAwareSessionFactory()
关闭此标志以使用Hibernate的默认getCurrentSession()行为公开纯Hibernate SessionFactory,仅支持纯JTA同步。或者,只需重写相应的Hibernate属性“ hibernate.current_session_context_class”。