小编典典

Hibernate Create Criteria两次连接同一张表-尝试了2种方法,但有2个差异错误

hibernate

我想为以下本机sql创建创建条件。

不幸的是,我两次使用createCriteria时遇到重复的关联路径错误。当我尝试使用Restrictions.sqlRestriction时。它无法提供我想要的SQL。

尝试1:创建条件-重复的关联路径

 Criteria criteria = getSession().createCriteria( Company.class );
                 criteria.createAlias( "customerCategories", "c1" );
                 criteria.add( Restrictions.in( "c1.customerCategory.customerCategoryId",
                         company.getBaseCustomerCategoryId() ) );
                 criteria.createAlias( "customerCategories", "c2" );
                 criteria.add( Restrictions.in( "c2.customerCategory.customerCategoryId",
                         company.getPromoCustomerCategoryId() ) );

尝试2:创建SQL限制-ORA-00920:由于“ where”,关系运算符无效

  Criteria criteria = getSession().createCriteria( Company.class );
                 criteria.add( Restrictions.sqlRestriction(
                         "INNER JOIN Company_Customercategory a on {alias}.companyId = a.companyId and a.CUSTOMERCATEGORYID = ?",
                         company.getBaseCustomerCategoryId(), LongType.INSTANCE ) );
                 criteria.add( Restrictions.sqlRestriction( 
                         "1=1 INNER JOIN Company_Customercategory b on {alias}.companyId = b.companyId
 and b.CUSTOMERCATEGORYID = ?", 
                         company.getPromoCustomerCategoryId(), LongType.INSTANCE) );

结果错误

select this_.* from Companies this_ where 
  INNER JOIN Company_Customercategory a 
  on this_.companyId = a.companyId 
  and a.CUSTOMERCATEGORYID = 1
  and 1=1 INNER JOIN Company_Customercategory b 
  on this_.companyId = b.companyId 
  and b.CUSTOMERCATEGORYID = 6

预期的SQL

select * from companies c
  inner join Company_Customercategory a
  on c.companyId = a.companyId
  and a.CUSTOMERCATEGORYID = 1
  inner JOIN Company_Customercategory b
  on a.companyId = b.companyId
  and b.CUSTOMERCATEGORYID = 6

感谢你的帮助。谢谢。


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2020-06-20

共1个答案

小编典典

关于2005年打开的问题,还有一个旧的Hibernate错误HHH-879org.hibernate.QueryException: duplicate association path仍在打开…

其他问题已关闭,但没有解决方案HHH-7882

因此,选项1)不太适合。

但是,在上述错误的意见的有用 的解决方法 是使用提及exists

因此,请使用两次sqlRestrictionexists并使用一个相关的子查询来过滤属性类别。您将获得唯一的 企业 连接到这两个类别。

crit.add( Restrictions.sqlRestriction( 
  "exists (select null from Company_Customercategory a where {alias}.company_Id = a.company_Id and a.CUSTOMERCATEGORYID = ?)",
  1, IntegerType.INSTANCE ) );
crit.add( Restrictions.sqlRestriction( 
  "exists (select null from Company_Customercategory a where {alias}.company_Id = a.company_Id and a.CUSTOMERCATEGORYID = ?)",
  6, IntegerType.INSTANCE ) );

这导致以下查询提供正确的结果

select this_.COMPANY_ID as COMPANY_ID1_2_0_, this_.COMPANY_NAME as COMPANY_NAME2_2_0_ 
from COMPANIES this_ 
where exists (select null from Company_Customercategory a 
              where this_.company_Id = a.company_Id and a.CUSTOMERCATEGORYID =  ?) and 
      exists (select null from Company_Customercategory a 
              where this_.company_Id = a.company_Id and a.CUSTOMERCATEGORYID = ?)
2020-06-20