小编典典

使用Transformer时休眠异常PropertyNotFoundException

hibernate

我正在使用hibernate和hql在Java代码中进行查询。但是我有这样一个例外:

Caused by: org.hibernate.PropertyNotFoundException: Could not find setter for 0 on class [my class]
    at org.hibernate.property.ChainedPropertyAccessor.getSetter(ChainedPropertyAccessor.java:44)

我不明白“ 0”的含义。以下是一些带有示例的细节:

我有几个表加入hql。表格如下:

A
- A_ID
- NAME

B
- B_ID
- A_ID

C
- C_ID
- B_ID
- LENGTH
- UNIT

类:

@Entity
@Table(name="A")
class A
{
    @Id
    @Column(name="A_ID", updatable=false)
    private Long id;

    @Column(name="NAME", nullable=false, length=10, updatable=false)
    private String name;

    @OneToMany(mappedBy="a", fetch=FetchType.LAZY, cascade={CascadeType.ALL})
    @JoinColumn(name="A_ID", nullable=false)
    private Set<B> bs;

    @Transient
    private Double length;

    @Transient
    private String unit;

    // Setters and getters
    ...
}

@Entity
@Table(name="B")
class B
{
    @Id
    @Column(name="B_ID", updatable=false)
    private Long id;

    @ManyToOne
    @JoinColumn(name="A_ID", nullable=false, insertable=true, updatable=false)
    private A a;

    @OneToMany(mappedBy="b", fetch=FetchType.LAZY, cascade={CascadeType.ALL})
    @JoinColumn(name="B_ID", nullable=false)
    private Set<C> cs;

    // Setters and getters
    ...
}

@Entity
@Table(name="C")
class C
{
    @Id
    @Column(name="C_ID", updatable=false)
    private Long id;

    @ManyToOne
    @JoinColumn(name="B_ID", nullable=false, insertable=true, updatable=false)
    private B b;

    @Column(name="LENGTH", nullable=false, updatable=false)
    private Double length;

    @Column(name="UNIT", nullable=false, length=10, updatable=false)
    private String unit;

    // Setters and getters
    ...
}

hql:

select a, sum(c.length) as length, min(c.unit) as unit
from A a
left outer join a.b as b
left outer join b.c as c
group by
a.id
a.name

查询:

Query query = session.createQuery(hql.toString()).setResultTransformer(Transformers.aliasToBean(A.class));

结果是对象“ A”的列表,其中包含收集的长度和单位。我不明白为什么会遇到这个例外。请给一些建议。


更新:

我编写了一个ResultTransformer并输出所有“别名”以查看问题:

-> 0
-> length
-> unit

似乎它还会用长度和单位来对待“ A”。我的HQL应该有问题吗?


阅读 309

收藏
2020-06-20

共1个答案

小编典典

发现问题:

即使HQL可以正确转换为sql,但是当ResultTransformer获取结果时,结果中将只有3个字段:

1. A
2. length
3. unit

无论A中有多少个字段,它们都将被汇总到单个字段“ A”中,并且由于我没有对此字段设置任何别名,因此它将被视为“字段0”。

因此,在我像这样更改HQL之后,问题解决了:

select a.id as id, a.name as name, sum(c.length) as length, min(c.unit) as unit
from A a
left outer join a.b as b
left outer join b.c as c
group by
a.id
a.name
2020-06-20