我在Hibernate（版本3.2.5）中很难将此查询（可直接在数据库上使用）表示为条件查询：

SELECT s.* 
  FROM ftp_status s 
 WHERE (s.datetime,s.connectionid) IN (SELECT MAX(f.datetime),
                                              f.connectionid 
                                         FROM ftp_status f
                                        GROUP BY f.connectionid);

到目前为止，这是我要解决的问题，它不起作用，并引发could not resolve property: datetime of: common.entity.FtpStatus错误消息：

Criteria crit = s.createCriteria(FtpStatus.class);
crit = crit.createAlias("connections", "c");
crit = crit.createAlias("id", "f");
ProjectionList proj = Projections.projectionList();
proj = proj.add(Projections.max("f.datetime"));
proj = proj.add(Projections.groupProperty("c.connectionid"));
crit = crit.setProjection(proj);
List<FtpStatus> dtlList = crit.list();

这是Netbeans 6.8直接从数据库生成的相关参考配置：

FtpStatus.hbm.xml-

<hibernate-mapping>
   <class name="common.entity.FtpStatus" table="ftp_status" catalog="common">
        <composite-id name="id" class="common.entity.FtpStatusId">
            <key-property name="siteid" type="int">
                <column name="siteid" />
            </key-property>
            <key-property name="connectionid" type="int">
                <column name="connectionid" />
            </key-property>
            <key-property name="datetime" type="timestamp">
                <column name="datetime" length="19" />
            </key-property>
        </composite-id>
        <many-to-one name="connections" class="common.entity.Connections" update="false" insert="false" fetch="select">
            <column name="connectionid" not-null="true" />
        </many-to-one>
        <many-to-one name="sites" class="common.entity.Sites" update="false" insert="false" fetch="select">
            <column name="siteid" not-null="true" />
        </many-to-one>
        <property name="upInd" type="boolean">
            <column name="up_ind" not-null="true" />
        </property>
        <property name="lastMessage" type="string">
            <column name="last_message" length="65535" not-null="true" />
        </property>
    </class>
</hibernate-mapping>

Connections.hbm.xml-

<hibernate-mapping>
    <class name="common.entity.Connections" table="connections" catalog="common">
        <id name="connectionid" type="java.lang.Integer">
            <column name="connectionid" />
            <generator class="identity" />
        </id>
        <property name="ip" type="string">
            <column name="ip" length="15" not-null="true" />
        </property>
        <property name="port" type="int">
            <column name="port" not-null="true" />
        </property>
        <property name="user" type="string">
            <column name="user" length="8" not-null="true" />
        </property>
        <property name="password" type="string">
            <column name="password" length="50" not-null="true" />
        </property>
        <set name="ftpStatuses" inverse="true">
            <key>
                <column name="connectionid" not-null="true" />
            </key>
            <one-to-many class="common.entity.FtpStatus" />
        </set>
    </class>
</hibernate-mapping>

我知道我丢失了一些东西，但是我对hibernate状态的谷歌搜索还没有发现它。或者，直接使用s.createSQLQuery()或进行SQL查询s.createQuery()也是可以接受的，但是编写该查询的成功率甚至更低。