我正在通过遵循一个教程来研究示例Spring Hibernate示例,并且陷入了异常说
Exception in thread "main" org.springframework.orm.hibernate4.HibernateSystemException: getFlushMode is not valid without active transaction; nested exception is org.hibernate.HibernateException: getFlushMode is not valid without active transaction
这是我的代码:
Person.java- 简单的POJO
public class Person { private Integer id; private String name; private String email; // Setters & Getters }
person.hbm.xml- 映射文件
<?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping> <class name="com.examples.model.Person" table="PERSON"> <id column="ID" name="id"> <generator class="increment" /> </id> <property name="name" column="NAME" /> <property name="email" column="EMAIL" /> </class> </hibernate-mapping>
PersonDao.java- 我的DAO类
import java.util.List; import org.hibernate.criterion.DetachedCriteria; import org.springframework.orm.hibernate4.support.HibernateDaoSupport; import com.examples.model.Person; public class PersonDao extends HibernateDaoSupport { public void insert(Person person) { getHibernateTemplate().save(person); } public List selectAll() { DetachedCriteria criteria = DetachedCriteria.forClass(Person.class); return getHibernateTemplate().findByCriteria(criteria); } }
PersonService.java- 服务层
public class PersonService { private PersonDao personDao; public PersonDao getPersonDao() { return personDao; } public void setPersonDao(PersonDao personDao) { this.personDao = personDao; } public void addPerson(Person person) { getPersonDao().insert(person); } public List<Person> fetchAllPersons() { return getPersonDao().selectAll(); } }
spring-config.xml -Spring配置文件:
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd"> <bean id="personService" class="com.examples.service.PersonService"> <property name="personDao" ref="personDao" /> </bean> <bean id="personDao" class="com.examples.dao.PersonDao"> <property name="hibernateTemplate" ref="hibernateTemplate" /> </bean> <bean id="hibernateTemplate" class="org.springframework.orm.hibernate4.HibernateTemplate"> <property name="sessionFactory" ref="sessionFactory" /> </bean> <bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="mappingResources"> <list> <value>com/examples/model/person.hbm.xml </value> </list> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop> <prop key="hibernate.current_session_context_class">thread</prop> </props> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="com.mysql.jdbc.Driver" /> <property name="url" value="jdbc:mysql://127.0.0.1:3306/hib" /> <property name="username" value="root" /> <property name="password" value="admin" /> </bean> </beans>
最后是我的 主程序-MainApp.java
public class MainApp { public static void main(String[] args) { System.out.println("************** BEGINNING PROGRAM **************"); ApplicationContext context = new ClassPathXmlApplicationContext( "spring-config.xml"); PersonService personService = (PersonService) context .getBean("personService"); Person person = new Person(); person.setName("Robin"); person.setEmail("robin@gmail.com"); personService.addPerson(person); System.out.println("Person : " + person + " added successfully"); List<Person> persons = personService.fetchAllPersons(); System.out.println("The list of all persons = " + persons); System.out.println("************** ENDING PROGRAM *****************"); } }
当我运行程序时,出现以下异常:
Exception in thread "main" org.springframework.orm.hibernate4.HibernateSystemException: getFlushMode is not valid without active transaction; nested exception is org.hibernate.HibernateException: getFlushMode is not valid without active transaction at org.springframework.orm.hibernate4.SessionFactoryUtils.convertHibernateAccessException(SessionFactoryUtils.java:216) at org.springframework.orm.hibernate4.HibernateTemplate.doExecute(HibernateTemplate.java:343) at org.springframework.orm.hibernate4.HibernateTemplate.executeWithNativeSession(HibernateTemplate.java:308) at org.springframework.orm.hibernate4.HibernateTemplate.save(HibernateTemplate.java:617) at com.examples.dao.PersonDao.insert(PersonDao.java:13) at com.examples.service.PersonService.addPerson(PersonService.java:21) at com.examples.MainApp.main(MainApp.java:24) Caused by: org.hibernate.HibernateException: getFlushMode is not valid without active transaction at org.hibernate.context.internal.ThreadLocalSessionContext$TransactionProtectionWrapper.invoke(ThreadLocalSessionContext.java:352) at com.sun.proxy.$Proxy6.getFlushMode(Unknown Source) at org.springframework.orm.hibernate4.HibernateTemplate.checkWriteOperationAllowed(HibernateTemplate.java:1134) at org.springframework.orm.hibernate4.HibernateTemplate$12.doInHibernate(HibernateTemplate.java:620) at org.springframework.orm.hibernate4.HibernateTemplate$12.doInHibernate(HibernateTemplate.java:617) at org.springframework.orm.hibernate4.HibernateTemplate.doExecute(HibernateTemplate.java:340) ... 5 more
我遵循了该SO帖子中给出的解决方案-Spring / HibernateException:如果没有活动的事务,createCriteria无效
然后我有一个例外说:
Exception in thread "main" org.springframework.dao.InvalidDataAccessApiUsageException: Write operations are not allowed in read-only mode (FlushMode.MANUAL): Turn your Session into FlushMode.COMMIT/AUTO or remove 'readOnly' marker from transaction definition.
请帮助我如何解决此问题?
如错误所述,您必须使用事务,因此在spring配置文件中声明事务管理器:
<bean id="txManager" class="org.springframework.orm.hibernate4.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory" /> </bean> <tx:advice id="txAdvice" transaction-manager="txManager"> <tx:attributes> <tx:method name="get*" read-only="true" /> <tx:method name="*" /> </tx:attributes> </tx:advice> <aop:config> <aop:pointcut id="personServiceOperation" expression="execution(* com.examples.service.PersonService.*(..))" /> <aop:advisor advice-ref="txAdvice" pointcut-ref="personServiceOperation" /> </aop:config>
在这里,我们还需要使用aopand tx命名空间,因此更新命名空间声明beans如下:
aop
tx
beans
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd">
最后删除配置文件中的以下行:
<prop key="hibernate.current_session_context_class">thread</prop>