创建像这样的结构后:
type Foo struct { name string } func (f Foo) SetName(name string) { f.name = name } func (f Foo) GetName() string { return f.name }
如何创建Foo的新实例并设置并获取名称?我尝试了以下方法:
p := new(Foo) p.SetName("Abc") name := p.GetName() fmt.Println(name)
没有打印任何内容,因为名称为空。那么如何设置结构中的字段?
工作操场
评论(和工作)示例:
package main import "fmt" type Foo struct { name string } // SetName receives a pointer to Foo so it can modify it. func (f *Foo) SetName(name string) { f.name = name } // Name receives a copy of Foo since it doesn't need to modify it. func (f Foo) Name() string { return f.name } func main() { // Notice the Foo{}. The new(Foo) was just a syntactic sugar for &Foo{} // and we don't need a pointer to the Foo, so I replaced it. // Not relevant to the problem, though. p := Foo{} p.SetName("Abc") name := p.Name() fmt.Println(name) }
测试并进行Go之旅,以了解有关方法和指针以及Go的基础知识的更多信息。