是否需要包装支持对象?我想做这个:
@RequestMapping(value = "/Test", method = RequestMethod.POST) @ResponseBody public boolean getTest(@RequestBody String str1, @RequestBody String str2) {}
并使用这样的JSON:
{ "str1": "test one", "str2": "two test" }
但是我必须使用:
@RequestMapping(value = "/Test", method = RequestMethod.POST) @ResponseBody public boolean getTest(@RequestBody Holder holder) {}
然后使用以下JSON:
{ "holder": { "str1": "test one", "str2": "two test" } }
那是对的吗?我的另一种选择是将更RequestMethod改为GET并@RequestParam在查询字符串中使用或@PathVariable与一起使用RequestMethod。
你是正确的,@ RequestBody带注释的参数应该可以容纳请求的整个内容并绑定到一个对象,因此你基本上必须使用选项。
如果你绝对想要你的方法,则可以执行一个自定义实现:
说这是你的json:
并且你想要将其绑定到此处的两个参数:
@RequestMapping(value = "/Test", method = RequestMethod.POST) public boolean getTest(String str1, String str2)
首先@JsonArg使用JSON路径(如所需信息的路径)定义一个自定义批注say(说):
public boolean getTest(@JsonArg("/str1") String str1, @JsonArg("/str2") String str2)
现在编写一个Custom HandlerMethodArgumentResolver,它使用上面定义的JsonPath来解析实际参数:
import java.io.IOException; import javax.servlet.http.HttpServletRequest; import org.apache.commons.io.IOUtils; import org.springframework.core.MethodParameter; import org.springframework.http.server.ServletServerHttpRequest; import org.springframework.web.bind.support.WebDataBinderFactory; import org.springframework.web.context.request.NativeWebRequest; import org.springframework.web.method.support.HandlerMethodArgumentResolver; import org.springframework.web.method.support.ModelAndViewContainer; import com.jayway.jsonpath.JsonPath; public class JsonPathArgumentResolver implements HandlerMethodArgumentResolver{ private static final String JSONBODYATTRIBUTE = "JSON_REQUEST_BODY"; @Override public boolean supportsParameter(MethodParameter parameter) { return parameter.hasParameterAnnotation(JsonArg.class); } @Override public Object resolveArgument(MethodParameter parameter, ModelAndViewContainer mavContainer, NativeWebRequest webRequest, WebDataBinderFactory binderFactory) throws Exception { String body = getRequestBody(webRequest); String val = JsonPath.read(body, parameter.getMethodAnnotation(JsonArg.class).value()); return val; } private String getRequestBody(NativeWebRequest webRequest){ HttpServletRequest servletRequest = webRequest.getNativeRequest(HttpServletRequest.class); String jsonBody = (String) servletRequest.getAttribute(JSONBODYATTRIBUTE); if (jsonBody==null){ try { String body = IOUtils.toString(servletRequest.getInputStream()); servletRequest.setAttribute(JSONBODYATTRIBUTE, body); return body; } catch (IOException e) { throw new RuntimeException(e); } } return ""; } }
现在,只需在Spring MVC中注册即可。有点涉及,但这应该可以正常工作。