在Go中,我将如何解码该XML响应?我尝试UnMarshal在自己的Answer结构上构建自定义方法,但是运气不高。
UnMarshal
Answer
<?xml version="1.0"?> <GetAssignmentResponse> <Answer><?xml version="1.0" encoding="UTF-8" standalone="no"?> <QuestionFormAnswers xmlns="http://mechanicalturk.amazonaws.com/AWSMechanicalTurkDataSchemas/2005-10-01/QuestionFormAnswers.xsd"> <Answer> <QuestionIdentifier>Q1HasEvents</QuestionIdentifier> <FreeText>no</FreeText> </Answer> </QuestionFormAnswers> </Answer> </GetAssignmentResponse>
像这样两次解码(在操场上尝试)
package main import ( "encoding/xml" "fmt" ) var data = `<?xml version="1.0"?> <GetAssignmentResponse> <Answer><?xml version="1.0" encoding="UTF-8" standalone="no"?> <QuestionFormAnswers xmlns="http://mechanicalturk.amazonaws.com/AWSMechanicalTurkDataSchemas/2005-10-01/QuestionFormAnswers.xsd"> <Answer> <QuestionIdentifier>Q1HasEvents</QuestionIdentifier> <FreeText>no</FreeText> </Answer> </QuestionFormAnswers> </Answer> </GetAssignmentResponse>` type Response struct { XMLName xml.Name `xml:"GetAssignmentResponse"` Answer string `xml:"Answer"` } type Answer struct { XMLName xml.Name `xml:"QuestionFormAnswers"` FreeText string `xml:"FreeText"` } func main() { v := Response{} err := xml.Unmarshal([]byte(data), &v) if err != nil { fmt.Printf("error: %v", err) return } fmt.Printf("Answer = %q\n", v.Answer) a := Answer{} err = xml.Unmarshal([]byte(v.Answer), &a) if err != nil { fmt.Printf("error: %v", err) return } fmt.Printf("Answer = %#v\n", a) }