在Swift中,您可以使用’is’检查对象的类类型。如何将其合并到“ switch”块中?
我认为这是不可能的,所以我想知道解决此问题的最佳方法是什么。
您绝对可以is在一个switch块中使用。请参阅Swift编程语言中的“对Any和AnyObject进行类型转换”(尽管Any当然不限于此)。他们有一个广泛的例子:
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for thing in things { switch thing { case 0 as Int: println("zero as an Int") case 0 as Double: println("zero as a Double") case let someInt as Int: println("an integer value of \(someInt)") case let someDouble as Double where someDouble > 0: println("a positive double value of \(someDouble)") // here it comes: case is Double: println("some other double value that I don't want to print") case let someString as String: println("a string value of \"\(someString)\"") case let (x, y) as (Double, Double): println("an (x, y) point at \(x), \(y)") case let movie as Movie: println("a movie called '\(movie.name)', dir. \(movie.director)") default: println("something else") } }