小编典典

Swift:快捷方式展开可选数组

swift

假设我们定义了一个可选数组:

var arrayOfOptionals: [String?] = ["Seems", "like", "an", nil, "of", "optionals"]

我可以在短时间内强行打开包装: var arrayForCrash = arrayOfOptionals.map { $0! }

但这会使应用程序崩溃,是否还有其他短途方法(无需显式展开)如何展开可选数组?


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2020-07-07

共1个答案

小编典典

此解决方案将为您提供一个新数组,其中所有值均已解包且所有nil均被滤除。

Swift 4.1:

let arrayOfOptionals: [String?] = ["Seems", "like", "an", nil, "of", "optionals"]
let arrayWithNoOptionals = arrayOfOptionals.compactMap { $0 }

Swift 2.0:

let arrayOfOptionals: [String?] = ["Seems", "like", "an", nil, "of", "optionals"]
let arrayWithNoOptionals = arrayOfOptionals.flatMap { $0 }

Swift 1.0:

let arrayOfOptionals: [String?] = ["Seems", "like", "an", nil, "of", "optionals"]
let arrayWithNoOptionals = arrayOfOptionals.filter { $0 != nil }.map { $0! }
2020-07-07