我有以下代码:
var encryptedByteArray: Array<UInt8>? do { let aes = try AES(key: "passwordpassword", iv: "drowssapdrowssap") encryptedByteArray = try aes.encrypt(Array("ThisIsAnExample".utf8)) } catch { fatalError("Failed to initiate aes!") } print(encryptedByteArray!) // Prints [224, 105, 99, 73, 119, 70, 6, 241, 181, 96, 47, 250, 108, 45, 149, 63] let hexString = encryptedByteArray?.toHexString() print(hexString!) // Prints e0696349774606f1b5602ffa6c2d953f
如何转换hexString回相同的UInt8字节数组?
hexString
UInt8
我问的原因是因为我想通过加密的十六进制字符串与服务器通信,所以我需要将其转换回UInt8字节数组以将字符串解码为其原始格式。
您可以将六进制字符串转换回UInt8数组,该数组每两个六个字符重复一次,并使用UInt8基数16初始化程序从中初始化UInt8:
编辑/更新: Xcode 14•Swift 5.1
extension StringProtocol { var hexaData: Data { .init(hexa) } var hexaBytes: [UInt8] { .init(hexa) } private var hexa: UnfoldSequence<UInt8, Index> { sequence(state: startIndex) { startIndex in guard startIndex < self.endIndex else { return nil } let endIndex = self.index(startIndex, offsetBy: 2, limitedBy: self.endIndex) ?? self.endIndex defer { startIndex = endIndex } return UInt8(self[startIndex..<endIndex], radix: 16) } } }
let string = "e0696349774606f1b5602ffa6c2d953f" let data = string.hexaData // 16 bytes let bytes = string.hexaBytes // [224, 105, 99, 73, 119, 70, 6, 241, 181, 96, 47, 250, 108, 45, 149, 63]
操场:
let hexaString = "e0696349774606f1b5602ffa6c2d953f" let bytes = hexaString.hexa // [224, 105, 99, 73, 119, 70, 6, 241, 181, 96, 47, 250, 108, 45, 149, 63]