从webservice(API)解码JSON时出现错误:
Could not cast value of type '__NSDictionaryM' (0x1037ad8a8) to 'NSArray' (0x1037ad470).
我的代码:
var kGetURL = "http://bitnami.local/cscart_demo/api/users" //var kGetURL = "http://localhost/fendy/getjson.php" var json : Array<AnyObject> = [] override func viewDidLoad() { super.viewDidLoad() start() } func getData(data : NSData){ //error at this line : json = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: nil) as! Array<AnyObject> //error tableView.reloadData() } func start(){ var url : NSURL = NSURL(string: kGetURL)! var data : NSData = NSData(contentsOfURL: url)! getData(data) }
如果我将URL更改为http://localhost/fendy/getjson.php,它的工作原理很好。
如果我的网址是http://bitnami.local/cscart_demo/api/users,我会收到错误消息
来自网络服务http://localhost/fendy/getjson.php的响应:
[{"id":"17","Name":"KFC","Message":"awesome"}, {"id":"18","Name":"McDonald","Message":"good"}, {"id":"23","Name":"Burger King","Message":"tasty"}, {"id":"38","Name":"Pizza hut","Message":"yummy"}, {"id":"39","Name":"Steak","Message":"very Delicious"}]
来自网络服务http://bitnami.local/cscart_demo/api/users的响应:
{"users": [{"user_id":"4","user_login":"user_4","is_root":"N","timestamp":"1441608048","user_type":"C","status":"A","firstname":"","lastname":"","email":"fendy.w@mvig.net","company":"","company_id":"1","company_name":"Simtech"}, {"user_id":"3","user_login":"customer","is_root":"N","timestamp":"1441604240","user_type":"C","status":"A","firstname":"Customer","lastname":"Customer","email":"customer@example.com","company":"Simtech","company_id":"1","company_name":"Simtech"}, {"user_id":"1","user_login":"admin","is_root":"Y","timestamp":"1441604240","user_type":"A","status":"A","firstname":"John","lastname":"Doe","email":"robby@mvig.net","company":"Your company","company_id":"0","company_name":null}], "params":{"page":1,"items_per_page":"10","sort_order":"asc","sort_by":"name","sort_order_rev":"desc","total_items":"3"}}
我认为它的样式是相同的,但是为什么不使用url http://bitnami.local/cscart_demo/api/users。有人可以帮忙吗?
bitnami响应以开头,{因此它是一个JSON对象,对应于NSDictionary。另一个以[表示数组。
{
NSDictionary
[
您需要将的类型更改json为Dictionary<String, AnyObject>,并按如下所示反序列化:
json
Dictionary<String, AnyObject>
json = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: nil) as! Dictionary<String, AnyObject>