我不想检查我的网址statusCode是否等于200,如果statusCode等于200,我创建了一个返回布尔值的函数,我使用的是dataTask,但我不知道如何返回值:
class func checkUrl(urlString: String) -> Bool{ let urlPath: String = urlString var url: NSURL = NSURL(string: urlPath)! var request: NSURLRequest = NSURLRequest(url: url as URL) var response: URLResponse? let session = Foundation.URLSession.shared var task = session.dataTask(with: request as URLRequest, completionHandler: {(data, response, error) in if let error = error { print(error) } if let data = data{ print("data =\(data)") } if let response = response { print("url = \(response.url!)") print("response = \(response)") let httpResponse = response as! HTTPURLResponse print("response code = \(httpResponse.statusCode)") if httpResponse.statusCode == 200{ return true } else { return false } } }) task.resume() }
中的返回if else返回错误:
if else
void函数中非预期的非无效返回值
为了返回值,您应该使用块。尝试像这样声明您的功能:
class func checkUrl(urlString: String, finished: ((isSuccess: Bool)->Void) { let urlPath: String = urlString var url: NSURL = NSURL(string: urlPath)! var request: NSURLRequest = NSURLRequest(url: url as URL) var response: URLResponse? let session = Foundation.URLSession.shared var task = session.dataTask(with: request as URLRequest, completionHandler: {(data, response, error) in if let error = error { print(error) } if let data = data{ print("data =\(data)") } if let response = response { print("url = \(response.url!)") print("response = \(response)") let httpResponse = response as! HTTPURLResponse print("response code = \(httpResponse.statusCode)") if httpResponse.statusCode == 200{ finished(isSuccess: true) } else { finished(isSuccess: false) } } }) task.resume() }
然后这样称呼它:
checkUrl("http://myBestURL.com", finished { isSuccess in // Handle logic after return here })
希望这会有所帮助。