小编典典

如何在Swift 3中从Struct数组制作JSON?

swift

我有一个问题JSON要从中的结构数组Swift3。我搜索了Stack Overflow,没有任何帮助(这里是屏幕截图)。我有一个struct这样的:

public struct ProductObject {
    var prodID: String
    var prodName: String
    var prodPrice: String
    var imageURL: String
    var qty: Int
    var stock: String
    var weight: String

    init(prodID: String, prodName: String, prodPrice: String, imageURL: String, qty: Int, stock: String, weight: String){
        self.prodID = prodID
        self.prodName = prodName
        self.prodPrice = prodPrice
        self.imageURL = imageURL
        self.qty = qty
        self.stock = stock
        self.weight = weight
    }
}

以及该结构的数组:

private var productsArray = [ProductObject]()

当数组不为空时,然后我尝试在另一个类中打印它,它在调试器中显示:

[app.cartclass.ProductObject(prodID: "2", prodName: "produk 2", prodPrice: "IDR 1000000", imageURL: "someURL", qty: 1, stock: "11", weight: "200")]

数组无效JSON object。如何使其成为有效JSON对象?而且我想知道“
app.cartclass.ProductObject”这一部分是否有问题,以使其有效JSON object

编辑:

这是我序列化为的方法JSON

var products = [String:Any]()
    for j in 0 ..< cart.numberOfItemsInCart()  {
        products=["\(j)":cart.getAllProduct(atIndex: j)]
    }
    if let valid = JSONSerialization.isValidJSONObject(products) {
        do {
            let jsonproducts = try JSONSerialization.data(withJSONObject: products, options: .prettyPrinted) as! [String:Any]
            //print(jsonproducts)
        } catch let error as NSError {
            print(error)
        }
     } else {
         print("it is not a valid JSON object");
     }

阅读 314

收藏
2020-07-07

共1个答案

小编典典

如果要从自定义对象生成JSON,则首先需要将自定义对象转换为Dictionary,因此在ProductObject结构中创建一个如下所示的函数。

func convertToDictionary() -> [String : Any] {
    let dic: [String: Any] = ["prodID":self.prodID, "prodName":self.prodName, "prodPrice":self.prodPrice, "imageURL":self.imageURL, "qty":qty, "stock":stock, "weight":weight]
    return dic
}

现在使用此函数从自定义对象数组生成字典数组ProductObject

private var productsArray = [ProductObject]()
let dicArray = productsArray.map { $0.convertToDictionary() }

dicArray是由类型组成的[[String:Any]],现在您可以用来JSONSerialization从中生成JSON字符串dicArray

if let data = try? JSONSerialization.data(withJSONObject: dicArray, options: .prettyPrinted) {
    let str = String(bytes: data, encoding: .utf8)
    print(str)
}
2020-07-07