小编典典

UIColor扩展便利初始化无法正常工作

swift

convenience init(red:Int,green:Int,blue:Int,alpha:CGFloat) {
    var red:   CGFloat = CGFloat(red)/255.0
    var green: CGFloat = CGFloat(green)/255.0
    var blue:  CGFloat = CGFloat(blue)/255.0
    self.init(red:red, green:green, blue:blue, alpha:alpha)
}

我编写了上面的代码,以提供更方便的方式来声明自定义uicolor。但是以某种方式,它通过调用自身直到堆栈溢出而使我的应用程序崩溃。怎么了

另外,我只是意识到我没有明确调用此init函数。但是,UIColor.whiteColor()当发生此错误时,我正在打电话。当然,如果我显式调用此函数,仍然会发生错误!


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2020-07-07

共1个答案

小编典典

我认为这样做不会带来任何不便:

let myCustomColorHSBa = UIColor(hue: 120/360, saturation: 0.25 , brightness: 1.0 , alpha: 1)
let myCustomColorRGBa = UIColor(red: 191/255, green: 1, blue: 191/255, alpha: 1)

但是如果您真的需要一个,可以按照以下步骤操作:

extension UIColor {
    convenience init(red: Int = 0, green: Int = 0, blue: Int = 0, opacity: Int = 255) {
        precondition(0...255 ~= red   &&
                     0...255 ~= green &&
                     0...255 ~= blue  &&
                     0...255 ~= opacity, "input range is out of range 0...255")
        self.init(red: CGFloat(red)/255, green: CGFloat(green)/255, blue: CGFloat(blue)/255, alpha: CGFloat(opacity)/255)
    }
}

UIColor(red: 255)               // r 1.0 g 0.0 b 0.0 a 1.0  (Red)
UIColor(red: 255, green: 255)   // r 1.0 g 1.0 b 0.0 a 1.0  (Yellow)
UIColor(red: 255, blue: 255)    // r 1.0 g 0.0 b 1.0 a 1.0  (Magenta)

UIColor(green: 255)             // r 0.0 g 1.0 b 0.0 a 1.0  (Green)
UIColor(green: 255, blue: 255)  // r 0.0 g 1.0 b 1.0 a 1.0  (Cyan)

UIColor(blue: 255)              // r 0.0 g 0.0 b 1.0 a 1.0  (Blue)
UIColor(red: 255, green: 192, blue: 203)  // r 1.0 g 0.753 b 0.796 a 1.0 (Pink)
UIColor(red: 255, green: 215)   // r 1.0 g 0.843 b 0.0 a 1.0 (Gold)
2020-07-07