小编典典

searchDisplayController,UITableView,Core Data和Swift

swift

尝试使用进行表格搜索searchDisplayController。配置了数据过滤后,搜索对话框将起作用。现在,我想使用一种prepareForSegue将当前值发送indexPath到新方法UIViewController

import UIKit
import CoreData

class MainTableViewController: UITableViewController {

var results:AddrBook[]=[]
var searchResults:AddrBook[]=[]

init(style: UITableViewStyle) {
    super.init(style: style)
}

init(coder aDecoder: NSCoder!) {
    super.init(coder: aDecoder)
}

override func viewDidLoad() {
    super.viewDidLoad()

}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
}

override func viewDidAppear(animated: Bool) {
    let request = NSFetchRequest(entityName: "Person")
    request.returnsObjectsAsFaults = false
    let appDelegate:AppDelegate = (UIApplication.sharedApplication().delegate as AppDelegate)
    let context:NSManagedObjectContext = appDelegate.managedObjectContext
    results  = context.executeFetchRequest(request, error: nil) as AddrBook[]
    self.tableView.reloadData()
}

override func numberOfSectionsInTableView(tableView: UITableView?) -> Int {
    return 1
}

override func tableView(tableView: UITableView!, numberOfRowsInSection section: Int) -> Int {
    if tableView == self.searchDisplayController.searchResultsTableView {
        return searchResults.count
    } else {
        return results.count
    }
}

override func tableView(tableView: UITableView!, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell! {
    var cell = tableView.dequeueReusableCellWithIdentifier("Cell") as? UITableViewCell

    if !cell {
        cell = UITableViewCell(style: UITableViewCellStyle.Value1, reuseIdentifier: "Cell")
    }

    if tableView == self.searchDisplayController.searchResultsTableView {
        cell!.textLabel.text = searchResults[indexPath.row].lastname + " " + searchResults[indexPath.row].firstname
        cell!.detailTextLabel.text = searchResults[indexPath.row].phonenumber
    } else {
        cell!.textLabel.text = results[indexPath.row].lastname + " " + results[indexPath.row].firstname
        cell!.detailTextLabel.text = results[indexPath.row].phonenumber
    }



    return cell
}

override func tableView(tableView: UITableView!, didSelectRowAtIndexPath indexPath: NSIndexPath!) {
    if tableView == self.searchDisplayController.searchResultsTableView {
        self.performSegueWithIdentifier("editPerson", sender : self)
    }
}

override func prepareForSegue(segue: UIStoryboardSegue!, sender: AnyObject?) {

    var indexPath = NSIndexPath()
    if self.tableView == self.searchDisplayController.searchResultsTableView {
        NSLog("Trying recieve indexPath from Search")
        indexPath = self.searchDisplayController.searchResultsTableView.indexPathForSelectedRow()
        NSLog("indexPath from Search")
    }
    else {
        indexPath = self.tableView.indexPathForSelectedRow()
        NSLog("IndexPath from main table")
    }

    let destViewController:DetailViewController! = segue.destinationViewController as DetailViewController

    if segue.identifier == "editPerson" {
        destViewController.receivedPerson = results
        destViewController.indexPath = indexPath
        NSLog("Selected person ID: \(results[indexPath.row].idperson)")
    }
}

override func tableView(tableView: UITableView?, canEditRowAtIndexPath indexPath: NSIndexPath?) -> Bool {
    return true
}


override func tableView(tableView: UITableView!, commitEditingStyle editingStyle: UITableViewCellEditingStyle, forRowAtIndexPath indexPath: NSIndexPath!) {

    let request = NSFetchRequest(entityName: "Person")
    request.returnsObjectsAsFaults = false
    let appDelegate:AppDelegate = (UIApplication.sharedApplication().delegate as AppDelegate)
    let context:NSManagedObjectContext = appDelegate.managedObjectContext

    if editingStyle == .Delete {
        context.deleteObject(results[indexPath.row])
        context.save(nil)
    }

    results.removeAtIndex(indexPath.row)
    tableView.deleteRowsAtIndexPaths([indexPath], withRowAnimation: .Fade)

}

func filterContentForSearchText (searchText: String) {
    searchResults = results.filter{
        ($0.lastname as NSString).localizedCaseInsensitiveContainsString("\(searchText)")
    }
}

func searchDisplayController(controller: UISearchDisplayController!, shouldReloadTableForSearchString searchString: String!) -> Bool {
    self.filterContentForSearchText (searchString)
    return true
}

}

在函数prepareForSegue条件中,self.tableView ==
self.searchDisplayController.searchResultsTableView不满足。

始终分配indexPath = self.tableView.indexPathForSelectedRow()代替indexPath = self.searchDisplayController.searchResultsTableView.indexPathForSelectedRow()。如果在搜索结果中选择一行,则会导致错误。

链接到Dropbox上的项目:https
:
//www.dropbox.com/s/bqv46nkoa4s3ibg/lesson-12-2-swift%203.zip


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2020-07-07

共1个答案

小编典典

self.tableView 是主表格视图,因此条件

if self.tableView == self.searchDisplayController.searchResultsTableView

永远不会是真的。但是您可以检查搜索是否处于活动状态:

if self.searchDisplayController.active {
    // index path from search table ... 
} else {
    // index path from main table ...
}
2020-07-07