小编典典

如何在React Router v4中嵌套路由?

reactjs

有没有办法在React Router v4中嵌套路由?

这有效:

  <Router basename='/app'>
    <main>
      <Route path='/' component={AppBar} />
      <Route path='/customers' component={Customers} />
    </main>
  </Router>

这不是:

  <Router basename='/app'>
    <Route path='/' component={AppBar}>
      <Route path='/customers' component={Customers} />
    </Route>
  </Router>

客户组成部分:

import React, { Component, PropTypes } from 'react'
import styled from 'styled-components'

export default class Customers extends Component {
  render () {
    return (
      <Container>
        <h1>Customers</h1>
      </Container>
    )
  }
}

const Container = styled.section`
  height: 100%;
  padding: 15px;
  overflow: auto;
`

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2020-07-22

共1个答案

小编典典

到目前为止,我发现的最佳模式。

// main app
<div>
    // not setting a path prop, makes this always render
    <Route component={AppShell}/>
    <Switch>
        <Route exact path="/" component={Login}/>
        <Route path="/dashboard" component={AsyncDashboard(userAgent)}/>
        <Route component={NoMatch}/>
    </Switch>
</div>

我可以继续将其嵌套在组件中,并且一切都很好,包括hmr(如果使用webpack,请不要忘记设置output.publicPath"/"

// dashboard component
<div>
    // the same way as before, not setting a path prop
    // makes it render on every /dashboard/** request 
    <Route component={DashboardTAB}/>
    <Switch>
        // longer path (with same root) than others first
        <Route path="/dashboard/graphs/longerpath" component={GraphForm}/>
        <Route path="/dashboard/graphs" component={Graphs}/>
        <Route path="/dashboard/workers" component={List}/>
        <Route path="/dashboard/insert" component={InsertComponent}/>
    </Switch>
</div>
2020-07-22