我有以下性质的查询

Category1(name: $cat1){
   Category2(secondName: $cat2){
      secondName
    }}

我的架构如下：

const Query = new GraphQLObjectType({
name: 'Query',
fields: {
    Category1: {
        type: new GraphQLList(Category1Type),
        args: { name },
        resolve: resolveCategory1
    }}
})

然后Category1Type定义为：

const Category1Type = new GraphQLObjectType({
    name: 'Category1',
    description: '<>',
    fields: () => ({
        name: { type: GraphQLString },
        category2: {
            type: new GraphQLList(CategoryType2),
            args: { secondName },
            resolve: resolveCategory2
        }
    })
});

为了简单起见，假设category2像这样：

const Category2Type = new GraphQLObjectType({
    name: 'Category2',
    description: '<>',
    fields: () => ({
        name: { type: GraphQLString },
    })
});

现在，我想获取Category1下的所有Category2项目，并带有过滤选项，如下所示：

Category1(name: $name){
   name
   category2(name: $name){
      name 
}}

我的解析器的定义如下：

    # Category1 resolver
    function cat1resolve (root, args) {
return SELECT * from data WHERE category1_name = args.name
}

    # Category2 resolver
    function cat2Resolve (root, args) {
return SELECT * from data WHERE category1_name = rootargs.name and categort2_name = args.secondName }

现在的问题是cat2Resolve的’resolver’无法看到或接收rootargs.name来执行这种过滤。