小编典典

将jQuery帖子发送到Google API的Access-Control-Allow-Origin错误

ajax

我读了很多有关“ Access-Control-Allow-Origin”错误的信息,但我不明白我必须解决的问题:(

我正在使用Google Moderator
API,但是当我尝试添加新系列时,收到以下消息:

XMLHttpRequest cannot load 
https://www.googleapis.com/moderator/v1/series?key=[key]
&data%5Bdescription%5D=Share+and+rank+tips+for+eating+healthily+on+the+cheaps!
&data%5Bname%5D=Eating+Healthy+%26+Cheap
&data%5BvideoSubmissionAllowed%5D=false. 
Origin [my_domain] is not allowed by Access-Control-Allow-Origin.

我尝试使用和不使用回调参数,都尝试将“ Access-Control-Allow-Origin *”添加到标题中。而且我不知道如何在这里使用$
.getJSON(如果适用),因为我必须添加Authorization标头,而且如果没有$ .ajax中的beforeCall,我也不知道该怎么做:/

这个黑暗的你有光吗?

那是代码:

<script src="http://www.google.com/jsapi"></script>

<script type="text/javascript">

var scope = "https://www.googleapis.com/auth/moderator";
var token = '';

function create(){
     if (token == '')
      token = doCheck();

     var myData = {
      "data": {
        "description": "Share and rank tips for eating healthily on the cheaps!", 
        "name": "Eating Healthy & Cheap", 
        "videoSubmissionAllowed": false
      }
    };

    $.ajax({

        url: 'https://www.googleapis.com/moderator/v1/series?key='+key,
        type: 'POST',
        callback: '?',
        data: myData,
        datatype: 'application/json',
        success: function() { alert("Success"); },
        error: function() { alert('Failed!'); },
        beforeSend: setHeader

    });
}

function setHeader(xhr) {

  xhr.setRequestHeader('Authorization', token);
}

function doLogin(){ 
    if (token == ''){
       token = google.accounts.user.login(scope);
    }else{
       alert('already logged');
    }
}


function doCheck(){             
    token = google.accounts.user.checkLogin(scope);
    return token;
}
</script>
...
...
<div data-role="content">
    <input type="button" value="Login" onclick="doLogin();">
    <input type="button" value="Get data" onclick="getModerator();">
    <input type="button" value="Create" onclick="create();">
</div><!-- /content -->

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2020-07-26

共1个答案

小编典典

我解决了将dataType参数修改为 dataType:’jsonp’ 并添加 crossDomain:true 的Access-Control-
Allow-Origin错误 __

$.ajax({

    url: 'https://www.googleapis.com/moderator/v1/series?key='+key,
    data: myData,
    type: 'GET',
    crossDomain: true,
    dataType: 'jsonp',
    success: function() { alert("Success"); },
    error: function() { alert('Failed!'); },
    beforeSend: setHeader
});
2020-07-26