尝试实施ajax登录/注册过程(不带身份验证的刷新站点)。使用Cookie来保存状态。我以为我现在就拥有此功能,但是由于某种原因,浏览器在从服务器取回cookie后仍未设置cookie。有人可以帮忙吗?这是请求和响应头:
Request URL:http://api.site.dev/v1/login Request Method:POST Status Code:200 OK
请求标题
Accept:application/json, text/plain, */* Accept-Charset:ISO-8859-1,utf-8;q=0.7,*;q=0.3 Accept-Encoding:gzip,deflate,sdch Accept-Language:en-US,en;q=0.8 Connection:keep-alive Content-Length:57 Content-Type:application/json;charset=UTF-8 Host:api.site.dev Origin:http://site.dev Referer:http://site.dev/ User-Agent:Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_2) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.101 Safari/537.11 withCredentials:true X-Requested-With:XMLHttpRequest Request Payload {"email":"calvinfroedge@gmail.com","password":"foobar"}
响应标题
Access-Control-Allow-Credentials:true Access-Control-Allow-Headers:X-Requested-With, Content-Type, withCredentials Access-Control-Allow-Methods:GET, POST, PUT, DELETE, OPTIONS Access-Control-Allow-Origin:http://site.dev Connection:Keep-Alive Content-Length:19 Content-Type:application/json Date:Tue, 08 Jan 2013 18:23:14 GMT Keep-Alive:timeout=5, max=99 Server:Apache/2.2.22 (Unix) DAV/2 PHP/5.4.7 mod_ssl/2.2.22 OpenSSL/0.9.8r Set-Cookie:site=%2B1THQQ%2BbZkEwTYFvXFVV5fxi00l2K%2B6fvt9SuHACTNsEwUGzDSUckt38ZeDsNbZSsqzHmPMWRLc84eDLZzh8%2Fw%3D%3D; expires=Thu, 10-Jan-2013 18:23:14 GMT; path=/; domain=.site.dev; httponly X-Powered-By:PHP/5.4.7
我还在服务器返回的Chrome网络工具中看到了cookie:
响应Cookie
Name: site Value: %2B1THQQ%2BbZkEwTYFvXFVV5fxi00l2K%2B6fvt9SuHACTNsEwUGzDSUckt38ZeDsNbZSsqzHmPMWRLc84eDLZzh8%2Fw%3D%3D Domain: .site.dev Path: / Expires: Session Size: 196 Http: ✓
必须通过将“ withCredentials”设置设置为true来发出AJAX请求(仅在XmlHttpRequest2和fetch中可用):
var req = new XMLHttpRequest(); req.open('GET', 'https://api.bobank.com/accounts', true); // force XMLHttpRequest2 req.setRequestHeader('Content-Type', 'application/json; charset=utf-8'); req.setRequestHeader('Accept', 'application/json'); req.withCredentials = true; // pass along cookies req.onload = function() { // store token and redirect let json; try { json = JSON.parse(req.responseText); } catch (error) { return reject(error); } resolve(json); }; req.onerror = reject;
如果您需要有关CORS,API安全性和cookie的详细说明,则该答案不适合StackOverflow注释。看看我写的这篇文章:http : //www.redotheweb.com/2015/11/09/api- security.html