如何使用Django，Ajax，jQuery提交表单而不刷新页面？

小编典典

如何使用Django，Ajax，jQuery提交表单而不刷新页面？

ajax

我是django的新手。我需要简单的例子。如何使用Django，Ajax，jQuery提交表单（发布）而不刷新页面？

这是我的表单，视图和模板：

views.py

from django.shortcuts import *
from django.template import RequestContext
from linki.forms import *

def advert(request):
    if request.method == "POST":
        form = AdvertForm(request.POST)

        if(form.is_valid()):
            print(request.POST['title'])
            message = request.POST['title']

        else:
            message = 'something wrong!'


        return render_to_response('contact/advert.html',
                {'message':message},
            context_instance=RequestContext(request))

    else:
        return render_to_response('contact/advert.html',
                {'form':AdvertForm()},
            context_instance=RequestContext(request))

forms.py（使用“ ModelForm”的表单）

from django import forms
from django.forms import ModelForm
from linki.models import Advert


class AdvertForm(ModelForm):
    class Meta:
        model = Advert

模板（表单html代码）

<html>
<head>

</head>
    <body>
    <h1>Leave a Suggestion Here</h1>
        {% if message %}
            {{ message }}
        {% endif %}
        <div>
            <form action="" method="post">{% csrf_token %}
                {{ form.as_p }}
                <input type="submit" value="Submit Feedback" />
            </form>
        </div>
    </body>
</html>

阅读 400

2020-07-26

共1个答案

小编典典

如果您打算将ajax提交与jquery一起使用，则不应从视图中返回html。我建议您改为这样做：

的HTML：

<html>
<head>
</head>
<body>
    <h1>Leave a Suggestion Here</h1>
        <div class="message"></div>
        <div>
            <form action="" method="post">{% csrf_token %}
                {{ form.as_p }}
                <input type="submit" value="Submit Feedback" />
            </form>
        </div>
</body>
</html>

$('#form').submit(function(e){
    $.post('/url/', $(this).serialize(), function(data){ ... 
       $('.message').html(data.message);
       // of course you can do something more fancy with your respone
    });
    e.preventDefault();
});

views.py

import json
from django.shortcuts import *
from django.template import RequestContext
from linki.forms import *

def advert(request):
    if request.method == "POST":
        form = AdvertForm(request.POST)

        message = 'something wrong!'
        if(form.is_valid()):
            print(request.POST['title'])
            message = request.POST['title']

        return HttpResponse(json.dumps({'message': message}))

    return render_to_response('contact/advert.html',
            {'form':AdvertForm()}, RequestContext(request))

这样您就可以将响应放入messagediv中。而不是返回纯HTML，您应该返回json。

2020-07-26