小编典典

Ajax无法通过readyState 1,为什么?

ajax

我正在尝试使此函数正常工作,该函数对参数url进行请求,然后将responseText发送给callback该函数。

似乎只能做到readyState 1(由于Firebug命令)。

这里是:

function Request(url, callback){
if (window.XMLHttpRequest) { // Mozilla, Safari, ...
    httpRequest = new XMLHttpRequest();
} else if (window.ActiveXObject) { // IE
    httpRequest = new ActiveXObject("Microsoft.XMLHTTP");
} else{
    return false;
}
httpRequest.onreadystatechange = function(){
    console.log(httpRequest.readyState);
    if (httpRequest.readyState == 4) {
        callback(httpRequest.responseText);
    }
};
console.log(httpRequest, url);
httpRequest.open('GET', url, true);
httpRequest.send(null);
}

阅读 391

收藏
2020-07-26

共1个答案

小编典典

我解决了分配onload事件而不是onreadystatechange的问题:

function Request(url, callback){
if (window.XMLHttpRequest) { // Mozilla, Safari, ...
    httpRequest = new XMLHttpRequest();
} else if (window.ActiveXObject) { // IE
    httpRequest = new ActiveXObject("Microsoft.XMLHTTP");
} else{
        return false;
}

var readyStateChange = function(){
    console.log(httpRequest.readyState);

    if (httpRequest.readyState == 4) {
                callback(httpRequest.responseText);
    }
};


if (isFirefox && firefoxVersion > 3) {
    httpRequest.onload = readyStateChange;
} else {
    httpRequest.onreadystatechange = readyStateChange;
}

console.log(httpRequest, url);
httpRequest.open('GET', url, true);
httpRequest.send(null);
}
2020-07-26