我有一个带有mysql数据的表,我添加了一个垃圾桶按钮,我想用ajax函数单击垃圾桶按钮时删除每一行,这是我的html:
<table border="1"> <?php $sql ="SELECT * FROM music"; $result = mysql_query($sql) or die(mysql_error()); while($row = mysql_fetch_object($result)){ echo '<tr><td>'.$row->file_name.'</td><td>'.$row->composer.'</td><td>'.$row->lyric.'</td><td>'.$row->music_thumb.'</td><td>'.' <a href="#" id="'.$row->msuic_id.'" class="trash" > جذف کردن </a> '.'</td></tr>'; } ?> </table>
和我的ajax功能在这里:
$(function(){ $('.trash').click(function(){ var del_id= $(this).attr('id'); var $ele = $(this).parent().parent(); $.ajax({ type:'POST', url:'delete.php', data:del_id, success: function(data){ if(data=="YES"){ $ele.fadeOut().remove(); }else{ alert("can't delete the row") } } }) }) });
还有我的“ delete.php”页面:
<?php include('../db_inc.php'); $music_number = "POST['del_id']"; echo '$music_number'; $qry = "DELETE FROM music WHERE msuic_id ='$music_number'"; $result=mysql_query($qry); ?>
我认为我的问题是ajax函数;谢谢
试试这个
$.ajax({ type:'POST', url:'delete.php', data:{del_id:del_id}, success: function(data){ if(data=="YES"){ $ele.fadeOut().remove(); }else{ alert("can't delete the row") } } }) })
并且也改变
$music_number = "POST['del_id']";
至
$music_number = $_POST['del_id'];