XMLHttpRequest在for循环中

小编典典

XMLHttpRequest在for循环中

ajax

我试图在for循环内发出几个服务器请求。我发现了[\这个问题，\并实施了建议的解决方案。但是，它似乎不起作用。

    for (var i = 1; i <= 10; i++)
    {
    (function(i) {
    if(<some conditions>)
    {
    if (window.XMLHttpRequest) {
        // code for IE7+, Firefox, Chrome, Opera, Safari
        xmlhttp[i]=new XMLHttpRequest();
      } else { // code for IE6, IE5
        xmlhttp[i]=new ActiveXObject("Microsoft.XMLHTTP");
      }
      xmlhttp[i].onreadystatechange=function() {
        if (xmlhttp[i].readyState==4 && xmlhttp[i].status==200) {
          document.getElementById("preselection").innerHTML=xmlhttp[i].responseText;
        }
      }
      xmlhttp[i].open("GET","getBuoys.php?q="+i,true);
      xmlhttp[i].send();
    }
})(i);
}

如果我删除了for循环并将所有xmlhttp [i]更改为xmlhttp，那么对于一个元素来说一切都很好，但是我无法发出多个请求。在此先感谢您的任何建议。

阅读 619

2020-07-26

共1个答案

小编典典

尝试下面的代码段

// JavaScript
window.onload = function(){

    var f = (function(){
        var xhr = [], i;
        for(i = 0; i < 3; i++){ //for loop
            (function(i){
                xhr[i] = new XMLHttpRequest();
                url = "closure.php?data=" + i;
                xhr[i].open("GET", url, true);
                xhr[i].onreadystatechange = function(){
                    if (xhr[i].readyState === 4 && xhr[i].status === 200){
                        console.log('Response from request ' + i + ' [ ' + xhr[i].responseText + ']'); 
                    }
                };
                xhr[i].send();
            })(i);
        }
    })();

};

// PHP [closure.php]
echo "Hello Kitty -> " . $_GET["data"];

响应

Response from request 0 [ Hello Kitty -> 0]
Response from request 1 [ Hello Kitty -> 1]
Response from request 2 [ Hello Kitty -> 2]

2020-07-26