在我的前端JavaScript应用程序中,我发出了ajax请求以从服务器获取数据。一旦获得数据,我想将该信息返回给视图。
var view_data; $.ajax({ url:"/getDataFromServer.json", //async: false, type: "POST", dataType: "json", success:function(response_data_json) { view_data = response_data_json.view_data; console.log(view_data); //Shows the correct piece of information return view_data; // Does not work. Returns empty data } }); // return view_data; --> Keeping the return outside of the ajax call works but then I need to make my ajax call synchronous in order for this return clause to be executed after the ajax call fetches data.
我该怎么做?
而不是data从success:返回来传递data给函数。
data
success
var view_data; $.ajax({ url:"/getDataFromServer.json", //async: false, type: "POST", dataType: "json", success:function(response_data_json) { view_data = response_data_json.view_data; console.log(view_data); //Shows the correct piece of information doWork(view_data); // Pass data to a function } }); function doWork(data) { //perform work here }